83 squard help plzzzzzzz
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Answer:
Step-by-step explanation:
In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).
The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.
Evaluating the integral gives use that it is equal to;
Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.
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Use the chain rule.
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx
Let u = 25sin²(x), such that dy/dx = dy/du · du/dx