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belka [17]
3 years ago
8

June runs 115 feet in 1 minute. About how many feet does she run per second?

Mathematics
2 answers:
vladimir1956 [14]3 years ago
4 0
1.91667 feet per second
iren [92.7K]3 years ago
3 0
1.966667 feet per second is the answer
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Elm Street is straight. Willard's house is at point H between the school at point S and
Vlad1618 [11]

Answer:

7.5 Miles.

Step-by-step explanation:

3 + 4.5 = 7.5 Miles.

4 0
2 years ago
Find all the zeros of the equation.<br><br> -3<img src="https://tex.z-dn.net/?f=%20%20x%5E%7B4%7D%20%7D%20" id="TexFormula1" tit
otez555 [7]


make the equation equal to 0
4 0
3 years ago
. Ralph’s Fill Dirt and Croissant Shop in Spencer makes both grand and petit croissants. Each grand requires 1 ounce of flour an
Gwar [14]

Answer:

1

Step-by-step explanation:

let G be the number of grand croisssants, and P the number of petit croissants :

we have that 1 ounce of flour and 2 ounces of butter result in one G.

additionally, we have that 1/4 ounce of flour and 1/3 ounce of butter result in one P.

Ralph has 4 ounces of flour and 6 ounces of butter, If he bakes more than 1 G then he will never use all of his ingredients!, let's see:

1 G:

he now has 3 ounces of flour, and 4 ounces of butter,

now we need to figure out how many P's we would obtain with such amounts:

let x be the number of P's

1/4*x = 3=>x=12\\ 1/3*x=4=>x=12

which is reasonable, Ralph can bake 12 P's,

now with more than 1 G:

2G:

Ralph has now 2 ounces of flour and 2 ounces of butter, now we have to figure out that x is the same using the remaining ingredients

1/4*x = 2=>x=8\\ 1/3*x=2=>x=6

This is impossible.

3G:

he runs out of butter.

There is the answer, he is able to bake 1 grand croissant and 12 petit croissants

7 0
3 years ago
Line j has an equation of y = x − 6.
chubhunter [2.5K]

Answer:

the answer is y = x-1

Step-by-step explanation:

y-y1 = m(x-x1)

y-9= 1×(x-10)

y=x-1

6 0
2 years ago
Use implicit differentiation to find an equation of the tangent line to the curve at the given point.
balu736 [363]
The tangent line to the curve can be determined by implicitly differentiating the equation of the curve. In this case, with the equation <span>y sin 12x = x cos 2y, (π/2, π/4), the implicit differentiation is 12 y cos 12x dx + sin 12 x dy = -2x sin 2y dy + cos 2y dx; dx (12 y cos 12x  - cos 2y) = dy (</span><span>-2x sin 2y - sin 12x). Hence

y' = (</span>12 y cos 12x  - cos 2y) / (<span>-2x sin 2y - sin 12x)</span>
6 0
3 years ago
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