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GarryVolchara [31]
3 years ago
10

Please answer ASAP!!!!!

Mathematics
1 answer:
blsea [12.9K]3 years ago
3 0

Answer:

This one show a positive relationship between x axis and y axis, as the x goes up, the y goes up too.

Step-by-step explanation:

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What’s the fraction fro 5/12+(-7/12)
Veseljchak [2.6K]

Answer:

-.167= -1/6

Step-by-step explanation:

5/12+(-7/12)

=(5 × 12) + (-7 × 12)

_______________

          12 × 12

=-24/144

= -24 ÷ 24

      ________

        144 ÷ 24

= - 1

       _______

              6

4 0
3 years ago
What’s this answer YALL IM STRUGGLING WITH MATH !!
saul85 [17]

Area: 4900

Perimeter: 280

5 0
3 years ago
Read 2 more answers
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




6 0
3 years ago
Please help me on this problem
kirill115 [55]

Answer:

y=-1/2x-3

Step-by-step explanation:

sorry if wrong form, there are like 6, but that is correct if in the right form

7 0
3 years ago
Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of
Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

\mathbf{L = (0,0)}

\mathbf{M = (3,0)}

\mathbf{N = (3,7)}

\mathbf{O = (0,7)}

P is the midpoint of LM.

So, we have:

\mathbf{P = \frac{LM}{2}}

\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}

\mathbf{P = (\frac{3}{2},0)}

Q is the midpoint of NO.

So, we have:

\mathbf{Q = \frac{NO}{2}}

\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}

\mathbf{Q = (\frac{3}{2},7)}

Distance PQ is calculated as follows:

\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

This gives:

\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}

\mathbf{PQ = \sqrt{ 7^2}}

\mathbf{PQ = 7}

Distance LO is calculated as follows:

\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}

\mathbf{LO = \sqrt{ 7^2}}

\mathbf{LO=7}

So, we have:

\mathbf{PQ = 7}

\mathbf{LO=7}

Thus:

\mathbf{PQ = LO}

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

8 0
2 years ago
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