First one :
10•5^2+4•-2^2=234
Second one :
-2(3•-2+-6)=24
<span>
−<span>2<span>(<span><span><span>(3)</span><span>(<span>−2</span>)</span></span>−6</span>)</span></span></span><span><span><span>
(<span>−2</span>)</span><span>(<span><span><span>(3)</span><span>(<span>−2</span>)</span></span>+<span>−6</span></span>)</span></span></span><span><span><span><span>
(<span>−2</span>)</span><span>(<span><span>(3)</span><span>(<span>−2</span>)</span></span>)</span></span>+<span><span>(<span>−2</span>)</span><span>(<span>−6</span>)</span></span></span></span><span>
<span>12+12</span></span><span><span>
24</span></span>
Last one :
2•-6(3•-6-5)
<span><span><span>
(2)</span><span>(<span>−6</span>)</span></span><span>(<span><span><span>(3)</span><span>(<span>−6</span>)</span></span>−5</span>)</span></span><span><span>
(<span><span>(2)</span><span>(<span>−6</span>)</span></span>)</span><span>(<span><span><span>(3)</span><span>(<span>−6</span>)</span></span>+<span>−5</span></span>)</span></span><span><span><span>
(<span><span>(2)</span><span>(<span>−6</span>)</span></span>)</span><span>(<span><span>(3)</span><span>(<span>−6</span>)</span></span>)</span></span>+<span><span>(<span><span>(2)</span><span>(<span>−6</span>)</span></span>)</span><span>(<span>−5</span>)</span></span></span><span>
216+60</span><span>
=276
Hoped I helped!</span>
Answer:
Step-by-step explanation:
Remember that our original exponential formula was y = a b x. You will notice that in these new growth and decay functions, the b value (growth factor) has been replaced either by (1 + r) or by (1 - r). The growth "rate" (r) is determined as b = 1 + r.
An exponential function of a^x (a>0) is always ln(a)*a^x, as a^x can be rewritten in e^(ln(a)*x). By deriving, the term (ln(a)) gets multiplied with a^x. The derivative shows, that the rate of change is similiar to the function itself. For 0<a<1, ln(a) becomes negative and so is the rate of change.
Linear models are used when a phenomenon is changing at a constant rate, and exponential models are used when a phenomenon is changing in a way that is quick at first, then more slowly, or slow at first and then more quickly.
The answer to this is f(x) = (3/2)x - 2.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Coordinates (x, y)
- Midpoint Formula:
Step-by-step explanation:
<u>Step 1: Define</u>
Point (2, 9)
Point (8, 1)
<u>Step 2: Identify</u>
(2, 9) → x₁ = 2, y₁ = 9
(8, 1) → x₂ = 8, y₂ = 1
<u>Step 3: Find Midpoint</u>
Simply plug in your coordinates into the midpoint formula to find midpoint
- Substitute in points [Midpoint Formula]:
- [Fractions] Add:
- [Fractions] Divide:
