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valentinak56 [21]
4 years ago
14

I need to solve y=a(x-h)²+k for a... Help!

Mathematics
2 answers:
viva [34]4 years ago
6 0

Answer: Just took the test and got the answer!! Step-by-step explanation: Look at the image down below ♡\( ̄▽ ̄)/♡

Serga [27]4 years ago
5 0
Thats the answer for a hope its helpful

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Problem
Sergeu [11.5K]

The lengths of HJ and JK are 50 and 72 respectively.

Given: J is between H and K. the length of HJ=2x+4, JK=3x+3, and HK=22.

The line HJ and JK are  collinear then the total length is given as: HJ+JK=HK

substitute values

⇒ (2x+4)+(3x+3)=22

⇒ 5x+7=22

⇒ 5x=22-7

⇒ 5x=15

⇒ x=3

Thus, the length of HJ is (2x+4)=(2*3+4)=10

And the length of JK is (3x+3)=(3*3+3)=12

Learn more about collinear lines here: brainly.com/question/27943430

#SPJ10

8 0
3 years ago
Read 2 more answers
Solving Exponential and Logarithmic Equations In Exercise, solve for x.<br> 4e2x - 3 - 5 = 0
Deffense [45]

Answer:

Value of x will be 0.1515

Step-by-step explanation:

We have given the equation 4e^{2x}-3-5=0

We have top fond the value of x using exponent and logarithmic property

So 4e^{2x}-3-5=0

4e^{2x}-8=0

4e^{2x}=8

e^{2x}=2

Taking log both side

lne^{2x}=ln2

2x=0.3010

x = 0.1515

4 0
3 years ago
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