Answer:
3
5
÷
j
=
3
8
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
(
3
5
)
⋅
8
=
j
⋅
3
Step-by-step explanation:Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
(
3
5
)
⋅
8
=
j
⋅
3
Answer:
(8, -5); x=8; y=-5
Step-by-step explanation:
i'll be solving via substitution
2x+3y=1; y=-2x+11
2x + 3(-2x +11) = 1
2x -6x +33 = 1
-4x = -32
x = 8
2(8) + 3y = 1
16 + 3y = 1
3y = -15
y = -5
(8, -5)
Check:
-5 = -2(8) + 11
-5 = -16 + 11
-5 = -5
Das is difference of 2 perfect squares
remember
a^2-b^2=(a-b)(a+b)
so
25x^4=(5x^2)^2
16y^2=(4y^2)
(5x^2)^2-(4y)^2=(5x^2-4y)(5x+4y)
cannot be factored further
Will start to distribute the 2 in (x-7)
so it can be (2x-2*7)=100
(2x-14)=100
2x=100+14
2x=114
x=114/2
x=57
