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Paha777 [63]
3 years ago
6

The function of the ___________________________ is to help the cell get rid of waste.

Chemistry
2 answers:
MA_775_DIABLO [31]3 years ago
6 0

Answer:

proteasome

Explanation:

One of the cell’s trash processors is called the proteasome. It breaks down proteins, the building blocks and mini-machines that make up many cell parts.

densk [106]3 years ago
4 0
The function of the lysosome is to help the cell get rid of waste
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5. A group decided to use 250.0 mL of vinegar and 24.0 grams of baking soda. What is the limiting
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Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

<h3>What is a limiting reactant?</h3>

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

To solve this problem, it is necessary to know the exact concentration of acetic acid in vinegar, because manufacturers produce many types of vinegar the with different concentrations. Most often, concentration of acetic acid in vinegar ranges from 4% to 8%. In this case, it is possible

to calculate the concentration of vinegar making the assumption that 250 ml of vinegar reacts completely with 24 grams of baking soda.

Acetic acid CH_3CO_2H  reacts with baking soda NaHCO_3 according to the equation:

CH_3CO_2H  + NaHCO_3 → CH_3CO_2Na + CO_2 + H_2O

1. Molar mass of NaHCO_3 is 23+1+12+16×3 = 84 g/mol

= \frac{1 mol \;NaHCO_3}{84 g \;NaHCO_3}

= \frac{24 g \;NaHCO_3 X 1 mol \;NaHCO_3}{84 g \;NaHCO_3}

=0.29 mol NaHCO_3

2. From the balanced equation we see that 1 mole of NaHCO_3 reacts with 1 mole of CH_3CO_2H , then 0.29 moles of NaHCO_3 react with 0.29 moles of CH_3CO_2H.

3. Mass of 1 mole of CH_3CO_2H is 12+ 1×3+12+16×2=60 g/mol

= \frac{0.29 mol \;CH_3CO_2H X \;60 g \;CH_3CO_2H }{1 mol \;CH_3CO_2H}

=17.4 g CH_3CO_2H

4. In this step density of vinegar is needed.

Making the assumption that concentration of acetic acid is 7%, we can calculate the mass of acetic acid in 250 ml of vinegar:

Mass of vinegar=Volume × density

= 250 ml ×1.0084 g/ml

=252 g

Mass of acetic acid = mass of vinegar × concentration ÷ 100%

= 252 g × 7% ÷ 100%

= 17.6 g.

17.6 g CH_3CO_2H is very close to 17.4 g CH_3CO_2H. It means, that 250 ml of vinegar with a concentration of acetic acid equal to 7% reacts completely with 24 g of baking soda.

Hence,  If the concentration of Acetic acid in vinegar is more than 7%, the limiting reactant is baking soda. If the concentration of Acetic acid in vinegar is less than 7%, the limiting reactant is vinegar.

Learn more about the limiting reactant here:

brainly.com/question/19654705

#SPJ1

4 0
2 years ago
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