Sodium chlorate decomposes into sodium chloride and oxygen.
The reaction is
NaClO3 --Δ--> NaCl + O2
The Δ means that heat is used
This equation is still not balanced.
Balancing the equation
2NaClO3 --Δ--> 2NaCl + 3O2
The equation is now balanced.
Explanation:
the pH of the solution defined as negatuve logarithm of 
ion concentration.
![pH=-\log[H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D)
1. Hydrogen ion concentration when pH of the solution is 11.
![11=-\log[H^+]](https://tex.z-dn.net/?f=11%3D-%5Clog%5BH%5E%2B%5D)
![[H^+]=1\times 10^{-11} mol/L](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D1%5Ctimes%2010%5E%7B-11%7D%20mol%2FL)
..(1)
At pH = 11, the concentration of ions is 
.
2. Hydrogen ion concentration when the pH of the solution is 6.
![6=-\log[H^+]'](https://tex.z-dn.net/?f=6%3D-%5Clog%5BH%5E%2B%5D%27)
![[H^+]'=1\times 10^{-6} mol/L](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%27%3D1%5Ctimes%2010%5E%7B-6%7D%20mol%2FL)
..(2)
At pH = 6, the concentration of ions is 
.
3. On dividing (1) by (2).
![\frac{[H^+]}{[H^+]'}=\frac{1\times 10^{-11} mol/L}{1\times 10^{-6} mol/L}=1\times 10^{-5}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BH%5E%2B%5D%7D%7B%5BH%5E%2B%5D%27%7D%3D%5Cfrac%7B1%5Ctimes%2010%5E%7B-11%7D%20mol%2FL%7D%7B1%5Ctimes%2010%5E%7B-6%7D%20mol%2FL%7D%3D1%5Ctimes%2010%5E%7B-5%7D%20)
The ratio of hydrogen ions in solution of pH equal to 11 to the solution of pH equal to 6 is 
.
4. Difference between the ions at both pH:
This means that Hydrogen ions in a solution at pH = 7 has 
ions fewer than in a solution at a pH = 6
There are <u>118</u> elements.
Answer:
–1065.25 KJ of energy.
Explanation:
From the question given above, the following data were obtained:
4FeO + O₂ —> 2Fe₂O₃ ΔH = –560.66 kJ
From the balanced equation above,
The formation of 2 moles of Fe₂O₃ released –560.66 kJ of energy.
Finally, we shall determine the amount of heat energy released when 3.8 moles of Fe₂O₃ are produced. This can be obtained as follow:
From the balanced equation above,
The formation of 2 moles of Fe₂O₃ released –560.66 kJ of energy.
Therefore, the formation of 3.8 moles of Fe₂O₃ will release
= (3.8 × –560.66)/2 = –1065.25 KJ of energy.
Thus, –1065.25 KJ of energy is released from the reaction.
