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3 years ago

A colloidal liquid suspended in a gas is called an aerosol. true or false

Chemistry

2 answers:

iragen [17]3 years ago

6 0

Aerosol:

Aerosol is a colloidal dispersion of liquid or solid in gas.

Thus a colloidal liquid suspended in a gas is called an aero sol is true

Aerosol is an example of colloidal dispersion and when a beam of light is fall on colloids then light is scattered means light is spread in all direction. It is a characteristic property of collides.

ella [17]3 years ago

6 0

I think the correct answer is true. A colloidal liquid suspended in a gas is called an aerosol. It can be directly emitted into the atmosphere or they can be formed in the atmosphere by condensation. Hope this answers the question. Have a nice day.

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Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g), Kgoal=? by making use of the followi

marta [7]

Answer : The value of $K_{goal}$ for the final reaction is, $1.238\times 10^{-7}$

Explanation :

The following equilibrium reactions are :

(1) $2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2$ $K_1=5.40\times 10^{-16}$

(2) $2H_2(g)+O_2(g)\rightleftharpoons 2H_2O(l)$ $K_2=1.06\times 10^{10}$

(3) $CH_3COOH(l)\rightleftharpoons 2C(s)+O_2(g)$ $K_3=2.68\times 10^{-9}$

The final equilibrium reaction is :

$CO_2(g)\rightleftharpoons C(s)+O_2(g)$ $K_{goal}=?$

Now we have to calculate the value of $K_{goal}$ for the final reaction.

First half the equation 1, 2 and 3 that means we are taking square root of equilibrium constant and then add all the equation 1, 2 and 3 that means we are multiplying all the equilibrium constant, we get the final equilibrium reaction and the expression of final equilibrium constant is:

$K_{goal}=\sqrt{K_1\times K_2\times K_3}$

Now put all the given values in this expression, we get :

$K_{goal}=\sqrt{(5.40\times 10^{-16})\times (1.06\times 10^{10})\times (2.68\times 10^{-9})}$

$K_{goal}=1.238\times 10^{-7}$

Therefore, the value of $K_{goal}$ for the final reaction is, $1.238\times 10^{-7}$

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3 years ago

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Marrrta [24]

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2 years ago

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Vitek1552 [10]

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2 years ago

Determine the total number of atoms contain in a 2.00 moles of Ni

spayn [35]

Answer:

2.00 moles of Ni has 1.2 *10^24 atoms

Explanation:

Step 1: Data given

Number of moles Ni = 2.00 moles

Number of Avogadro = 6.022*10^23 /mol

Step 2: Calculate number of atoms

Number of particles (=atoms) = Number of Avogadro * number of moles

Number of atoms = 6.022 * 10^23 /mol * 2.00 moles

Number of atoms = 1.2*10^24 atoms

2.00 moles of Ni has 1.2 *10^24 atoms

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3 years ago