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Andre45 [30]
3 years ago
9

Would copper exist in a monatomic form, a lattice or as molecules?

Chemistry
1 answer:
Elan Coil [88]3 years ago
3 0

you can not answer this question without specifying  the temperature and pressure of the copper

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What would the formula be for this model above?
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CH4

Explanation:

A= CH4

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Describe what constitutes Dalton's model of an atom
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The Constitution has seven parts to it it has amendments articles the Bill of Rights in the Declaration of Independence every Genia company of Charter
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The formation of a gas in a chemical reaction, due to ions changing places, often indicates that the reaction is which type?
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A virulence study was performed using Staphylococcus aureus in mice. It was determined that the LD50 for the S. aureus alpha-tox
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Answer:

S. aureus strain is less infectious, but its alpha-toxin is highly-toxic.

Explanation:

Given data:

LD50 for S. aureus alpha toxin 0.45 \mu g/kg

ID50 for same mouse density found to be 200,000

From the data information given above Staphylococcus aureus was done on mice. The result show that LD50 is found to be 0.45\mu g/kg and ID50 found to be 200,000 on same mouse population

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4 0
3 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl is
Rus_ich [418]

Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

                no. of moles of NaCl = mass of NaCl / molar mass

                no. of moles of NaCl = 0.45g / 58.44 g/mol

               no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
3 years ago
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