This is urgent!Does the element Francium have a smell or taste?

2 answers:

8 0

I don't think any one would know, really. It's highly radioactive (apparently) and has never been viewed in bulk, so we don't even know what it would look like as a metal! I would just say NO

zheka24 [161]3 years ago

4 0

It has No smell and unknown taste

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Compared to a solution with a ph value of 7, a solution with a thousand times greater hydronium ion concentration has a ph value

Mandarinka [93]

Answer:

pH = 4

Explanation:

pH is a base 10 logarithmic scale

1000 = 10^3

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2 years ago

At 20 ?C the vapor pressure of benzene (C6H6)is 75 torr, and that of toluene (C7H8) is 22 torr

tia_tia [17]

Answer:

(a) Benzene = 0.26; toluene = 0.74

(b) Benzene = 0.55

Explanation:

1. Calculate the composition of the solution

For convenience, let’s call benzene Component 1 and toluene Component 2.

According to Raoult’s Law,

$p_{1} = \chi_{1}p_{1}^{\circ}\\p_{2} = \chi_{2}p_{2}^{\circ}$

where

p₁ and p₂ are the vapour pressures of the components above the solution

χ₁ and χ₂ are the mole fractions of the components

p₁° and p₂° are the vapour pressures of the pure components.

Note that

χ₁ + χ₂ = 1

So,

$\begin{array}{rcl}p_{\text{tot}} &=& p_{1} + p_{2}\\p_{\text{tot}} & = & \chi_{1}p_{1}^{\circ} + (1 - \chi_{1})p_{2}^{\circ}\\36 & = & \chi_{1}\times 75 + (1 - \chi_{1}) \times 22 \\36 & = & 75\chi_{1} + 22 -22\chi_{1}\\14 & = & 53\chi_{1}\\\chi_{1} & = & \mathbf{0.26}\\\end{array}$

χ₁ = 0.26 and χ₂ = 0.74

2. Calculate the mole fraction of benzene in the vapour

In the liquid,

p₁ = χ₁p₁° = 0.26 × 75 mm = 20 mm

∴ In the vapour

$\chi_{1} = \dfrac{p_{1}}{p_{\text{tot}} } = \dfrac{\text{20 mm} }{\text{36 mm}} = 0.55$

Note that the vapour composition diagram below has toluene along the horizontal axis. The purple line is the vapour pressure curve for the vapour. Since χ₂ has dropped to 0.45, χ₁ has increased to 0.55.