If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
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y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4 </span>← to the nearest tenth<span>
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Answer:
Step-by-step explanation:
∵ The quadratic equation form is :
y = [1/2(b - k)] (x - a)² + (b + k)/2
Where (a , b) is the focus and directrix y = k
∵ The focus is (4 , -3) and directix is y = -6
∵ 
∴ 
∴
another way:
Assume that (x , y) is the general point on the parabola
∵ The distance between the directrix and (x , y) = the distance between the focus and (x , y)
By using the distance rule:
∵ (y - -6)² = (x - 4)² + (y - -3)² ⇒ (y + 6)² = (x - 4)² + (y + 3)
∴ y² + 12y + 36 = (x - 4)² + y² + 6y + 9
∴ 12y - 6y = (x - 4)² + 9 - 36
∴ 6y = (x - 4)² - 27 ⇒ ÷ 6
∴ y = 1/6 (x - 4)² - 9/2
Answer:
D
Step-by-step explanation:
Since BD and AE are parallel lines, then
∠BDC = ∠AED ( corresponding angles ), thus
4x - 5 = 97 - 2x ( add 2x to both sides )
6x - 5 = 97 ( add 5 to both sides )
6x = 102 ( divide both sides by 6 )
x = 17, hence
∠AED = 97 - 2x = 97 - (2 × 17) = 97 - 34 = 63°
∠BDE and ∠AED are same side interior angles and are supplementary, thus
10y - 3 + 63 = 180
10y + 60 = 180 ( subtract 60 from both sides )
10y = 120 ( divide both sides by 10 )
y = 12 → D
Set 4 is the correct answer because if you multiply 10 by 10 + 20 times 20, you will get 400 and when you multiply 30 by 30 you also get 400 which is equal to 400 there for you answer would be set 4.
Hope I helped if I did click the thx button ;)
Answer:
=34
Step-by-step explanation:
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