Okay so every triangle will have 3 angles that add to 180 degrees. You are given that A=65 which means that B + C will have to add to 115. You are given that B= (3x-10) and C=2x, plug this into B+C=115. So
3x-10+2x=115, isolate x, 5x=125, divide both sides by 5 and you get that x=25. This makes B=65, and C=50. Just to check, if you add these together you get 180 degrees.
Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
The 2nd graph show the rule
