Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
Answer:
Girls in Mr. Chang's class: 28 - 21 ; # girl students = # total students - # boy students ; 7 girl students.
Boys in Mr. Chang's class: 28 - 7 ; # boy students = # total students - girl students ; 21 boy students.
Answer:
m∠b = 76
Step-by-step explanation:
Opposite sides are congruent and measure the exact same thing
Answer:
X = 8, y = 8
Step-by-step explanation:
This question is an optimization problem. Two equations are going to be needed here
n = x+y
P = xy
Such that 64 = xy
When we divide through by x we get:
y = 64/x
So that n becomes:
n = x + 64/x
n = x+64x^-1
We take derivative
n' = 1-64x^-2
When n' = 0 then a min|max occurs
0 = 1-64x^-2
Such that:
64/x² = 1
Divide through by x²
64 = x²
x = √64
x = 8
Remember y = 64/x
So,
Y = 64/8
Y = 8.
X = 8, y = 8
Thank you!
Answer:
½log3 + ½logx
Step-by-step explanation:
½(log(3x))
½(log3 + logx)
½logx + ½log3
