Answer:
Step-by-step explanation:
I can't make specific statements about the proof because the midpoint is missing.
Givens
There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.
MN is bisected by the point on MN where the perpendicular meets MN
The Perpendicular Bisector is is common to both triangles.
Therefore the two triangles are congruent by SAS
PM = PN Parts contained in Congruent triangles are congruent.
None, a triangle need to have angles measuring 180 degrees , its only possible if the triangle has three angles equaling 60
Answer:
True. See the explanation and proof below.
Step-by-step explanation:
For this case we need to remeber the definition of linear transformation.
Let A and B be vector spaces with same scalars. A map defined as T: A >B is called a linear transformation from A to B if satisfy these two conditions:
1) T(x+y) = T(x) + T(y)
2) T(cv) = cT(v)
For all vectors
and for all scalars
. And A is called the domain and B the codomain of T.
Proof
For this case the tranformation proposed is t:
Where
For this case we have the following assumption:
1) The transpose of an nxm matrix is an nxm matrix
And the following conditions:
2) 
And we can express like this 
3) If
and
then we have this:

And since we have all the conditions satisfied, we can conclude that T is a linear transformation on this case.
Answer:
E
Step-by-step explanation:
Hope this helped
Answer: option d. the argument is valid by the law of detachment.
The law of detachment consists in make a conlcusion in this way:
Premise 1) a => b
Premise 2) a is true
Conclusion: Then, b is true
Note: the order of the premises 1 and 2 does not modifiy the argument.
IN this case:
Premise 1) angle > 90 => obtuse
Premise 2) angle = 102 [i.e. it is true that angle > 90]]
Conclusion: it is true that angle is obtuse