We need to account for both x values on either side of the length, and width.
Thus, the length becomes 10 + x + x = 10 + 2x
and the width becomes 5 + x + x = 5 + 2x
For the second question, I'm assuming we don't account for the area that is covered by the garden.
Then we can say that the path is measured by: (5 + 2x)(10 + 2x) - 50, which is the area of the garden itself.
(5 + 2x)(10 + 2x) - 50 = 54
Expanding the brackets:






x = -9, or x = 3/2
Since x > 0, then x ≠ -9
Thus, the only x-value we can take is x = 3/2
Y = 3x - 1
The format for slope intercept form is:
y = mx + b
m represents the slope and that was given so:
y = 3x + b
Now we have to substitute the value from the given point into “y” and “x” to solve for “b”
(2) = 3(1) + b
2 = 3 + b
-1 = b
Now that we know b we can substitute it into y = 3x + b to get the equation of the line
y = 3x - 1
~~hope this helps~~
655 rounded to the nearest hundred would be 700, so that could be an answer but some teachers say that you still have to keep the other digits. So it could be 700 or 1,766,700
Answer:
1,0
Step-by-step explanation:
No need to expand look at the roots of the brackets.
(x-1)=0
x=1
x^2 and -9x have roots 0
Think of it as whatever sets the expression to 0.