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3 years ago

9x^2+4y^2 = 36

Mathematics

2 answers:

Vladimir [108]3 years ago

7 0

Answer:

c.(0, -√5) and (0, √5)

Step-by-step explanation:

The equation represents an ellipse centered on origin (0,0). First, the formula is rearranged to its cannonical form:

$\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1$

The foci are located in the lines of the semimajor axes, so, the distance between the center and any of the foci is:

$c = \sqrt{9 - 4}$

$c = \sqrt{5}$

The foci are located at $(0, -\sqrt{5})$ and $(0,\sqrt{5})$ . Hence, the answer is C.

Afina-wow [57]3 years ago

6 0

The answer is c
hope this would help you

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Draw 2 supplementary angles. One angle is x-15 degrees and one is 2x degrees. What is the value of x in degrees?

Bond [772]

Answer:

Step-by-step explanation:

Since they are supplementary, it means the addition of both angles gives 180 degree.

$x - 15 + 2x = 180\\3x = 180 + 15\\3x = 195\\x = \frac{195}{3} \\x = 65$

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3 years ago

Which of the values shown are potential roots of f(x) = 3x3 – 13x2 – 3x + 45? Select all that apply.

galina1969 [7]

Answer:

All potential roots are 3,3 and $-\frac{5}{3}$ .

Step-by-step explanation:

Potential roots of the polynomial is all possible roots of f(x).

$f(x)=3x^3-13x^2-3x+45$

Using rational root theorem test. We will find all the possible or potential roots of the polynomial.

p=All the positive/negative factors of 45

q=All the positive/negative factors of 3

$p=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45$

$q=\pm 1,\pm 3$

All possible roots

$\frac{p}{q}=\pm 1,\pm 3,\pm 5\pm \pm 9,\pm 15\pm 45,\pm \frac{1}{3},\pm \frac{5}{3}$

Now we check each rational root and see which are possible roots for given function.

$f(1)= 3\times 1^3-13\times 1^2-3\times 1+45\Rightarrow 32\neq 0$

$f(-1)= 3\times (-1)^3-13\times (-1)^2-3\times (-1)+45\Rightarrow \neq 32$

$f(-3)= 3\times (-3)^3-13\times (-3)^2-3\times (-3)+45\Rightarrow \neq -144$

$f(3)= 3\times (3)^3-13\times (3)^2-3\times (3)+45\Rightarrow =0\\\\ \therefore x=3\text{ Potential roots of function}$

Similarly, we will check for all value of p/q and we get

$f(-5/3)=0$

Thus, All potential roots are 3,3 and $-\frac{5}{3}$ .

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2 years ago

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erastovalidia [21]

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8 0

3 years ago

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Find YW. YW = _<br><br> I just need the answer for YW no explanation needed.

KATRIN_1 [288]

Answer:

$YW=20\ units$

Step-by-step explanation:

we know that

In a parallelogram the diagonals bisect each other

The figure XYZW is a parallelogram

VW=VY

VX=VZ

<em>Find the value of b</em>

VW=VY

substitute the given values

$b+8=5b$

solve for b

$5b-b=8\\4b=8\\b=2$

Find the length of YW

$YW=YV+VW$ ----> by addition segment postulate

$YW=5b+b+8$

substitute the value of b

$YW=6(2)+8=20\ units$

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3 years ago

7b+1=-53 taking square roots

Aliun [14]

7.28 is the answer sorry if i’m wrong

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2 years ago