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3 years ago

9x^2+4y^2 = 36

Mathematics

2 answers:

Vladimir [108]3 years ago

7 0

Answer:

c.(0, -√5) and (0, √5)

Step-by-step explanation:

The equation represents an ellipse centered on origin (0,0). First, the formula is rearranged to its cannonical form:

$\frac{x^{2}}{4} + \frac{y^{2}}{9} = 1$

The foci are located in the lines of the semimajor axes, so, the distance between the center and any of the foci is:

$c = \sqrt{9 - 4}$

$c = \sqrt{5}$

The foci are located at $(0, -\sqrt{5})$ and $(0,\sqrt{5})$ . Hence, the answer is C.

Afina-wow [57]3 years ago

6 0

The answer is c
hope this would help you

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(b) The number of pairs of shoes that Bron'Tavious has is 20 pairs of shoes

Step-by-step explanation:

The given information are;

The number of shoes that Marquise has = 2 × The number of pairs of shoes that Bron'Tavious

The number of pairs of shoes that JayDarius has = The number of pairs of shoes that Bron'Tavious + 15

The total number of pairs of shoes they have all together = 95 pairs of shoes

Let the number of pairs of shoes that Bron'Tavious has = X. Therefore, we have;

The number of shoes that Marquise has = 2 × X

The number of pairs of shoes that JayDarius has = X + 15

The total number of pairs of shoes they have all together = X + X + 15 + 2 × X = 95

X + X + 15 + 2 × X = 95

4 × X + 15 = 95

4 × X = 95 - 15 = 80

X = 80/4 = 20

∴ X = 20

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The number of shoes that Marquise has = 40 pairs of shoes

(b) The number of pairs of shoes that Bron'Tavious has = X = 20

The number of pairs of shoes that Bron'Tavious has = 20 pairs of shoes

The number of pairs of shoes that JayDarius has = 35 pairs of shoes.

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