Wich phrase represents this expression 7x4+3

Which is equivalent sin^-1 (cos(pi/2))?Give your answer in radians

NNADVOKAT [17]

Answer:

Given the expression: $\sin^{-1}(\cos(\frac{\pi}{2}))$

Let the value of the given expression in radians be $\theta$

then;

$\sin^{-1}(\cos(\frac{\pi}{2})) =\theta$

$\cos \frac{\pi}{2} = \sin \theta$ ......[1]

We know the value of $\cos \frac{\pi}{2} = 0$

Substitute the given value in [1] we have;

$\sin \theta = 0$

Since, the value of $\sin \theta$ is 0, therefore, the value of $\theta$ is in the form of:

$\theta = n\pi$ ; where n is the integer.

At n =0, 1 and 2, {Since, n is the integer}

Value of $\theta =0, \pi$ and $2\pi$

therefore, the answer in radians either $0 , \pi$ or $2\pi$

6 0

3 years ago

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Consider the following differential equation. x^2y' + xy = 3 (a) Show that every member of the family of functions y = (3ln(x) +

Veronika [31]

Answer:

Verified

$y(x) = \frac{3Ln(x) + 3}{x}$

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{x}$

Step-by-step explanation:

Question:-

- We are given the following non-homogeneous ODE as follows:

$x^2y' +xy = 3$

- A general solution to the above ODE is also given as:

$y = \frac{3Ln(x) + C }{x}$

- We are to prove that every member of the family of curves defined by the above given function ( y ) is indeed a solution to the given ODE.

Solution:-

- To determine the validity of the solution we will first compute the first derivative of the given function ( y ) as follows. Apply the quotient rule.

$y' = \frac{\frac{d}{dx}( 3Ln(x) + C ) . x - ( 3Ln(x) + C ) . \frac{d}{dx} (x) }{x^2} \\\\y' = \frac{\frac{3}{x}.x - ( 3Ln(x) + C ).(1)}{x^2} \\\\y' = - \frac{3Ln(x) + C - 3}{x^2}$

- Now we will plug in the evaluated first derivative ( y' ) and function ( y ) into the given ODE and prove that right hand side is equal to the left hand side of the equality as follows:

$-\frac{3Ln(x) + C - 3}{x^2}.x^2 + \frac{3Ln(x) + C}{x}.x = 3\\\\-3Ln(x) - C + 3 + 3Ln(x) + C= 3\\\\3 = 3$

- The equality holds true for all values of " C "; hence, the function ( y ) is the general solution to the given ODE.

- To determine the complete solution subjected to the initial conditions y (1) = 3. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y( 1 ) = \frac{3Ln(1) + C }{1} = 3\\\\0 + C = 3, C = 3$

- Therefore, the complete solution to the given ODE can be expressed as:

$y ( x ) = \frac{3Ln(x) + 3 }{x}$

- To determine the complete solution subjected to the initial conditions y (3) = 1. We would need the evaluate the value of constant ( C ) such that the solution ( y ) is satisfied as follows:

$y(3) = \frac{3Ln(3) + C}{3} = 1\\\\y(3) = 3Ln(3) + C = 3\\\\C = 3 - 3Ln(3)$

- Therefore, the complete solution to the given ODE can be expressed as:

$y(x) = \frac{3Ln(x) + 3 - 3Ln(3)}{y}$

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6 0

3 years ago

There are 1265 students at Cypress Middle School. 42% of the students are enrolled in PE. Which equation could be used to repres

Dovator [93]

Answer:

0.42* 1265=x

Step-by-step explanation:

There are 1265 students in Cypress Middle School. So we already know one part of the equation. 42% of these students are in PE. So we know that 42% of these 1265 students are in PE. Of these means you probably have to multiply 42% and 1265. 42% = 0.42. So to write an equation we take the 0.42 and 1265 and put it together. Therefore, 0.42 times 1265=x.

7 0

3 years ago

moinca spent 4/7 hours listening beethtoven and brahms. she spent 2/5 hours listening to beethtoven. how many hours were spent l

Makovka662 [10]

He spent 2\2 hours listening to brahms

8 0

3 years ago

What is the simplified form of the following expression?<br>

ra1l [238]

(4/7)^3=.1865

6xyz/2xz simplifies to 3y

6 0

3 years ago

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