Answer:
Speed of Jet in Still Air = 265 miles per hour
Speed of Wind = 22 miles per hour
Step-by-step explanation:
Let x be speed of jet
and c be speed of wind
We know D = RT, where
D is distance
R is rate
T is time
For first leg:
1435 miles in 5 hours, the rate is:
Rate = 287 mph
For second leg:
1215 miles in 5 hours, the rate is:
Rate = 243 mph
So 287 is with wind and 243 against wind, thus we can write:
x + c = 287
x - c = 243
Adding gives us:
2x = 530
x = 265 miles per hour [still rate]
Speed of wind:
x + c = 287
265 + c = 287
c = 22 miles per hour [speed of wind]
The curved surface area is equal to about 354.53
Answer:
65.5
Step-by-step explanation:
I just took the assignment on edge. Good luck
