All categories

4 years ago

Adding and subtracting With Scientific notationPlease help

Mathematics

1 answer:

Tom [10]4 years ago

4 0

Answer:

0.131

Step-by-step explanation:

10^-2=0.01 so 0.01+6=0.06

0.06+0.071=0.131

You might be interested in

what is the unit price of 16 and 12.29, 32 and 19.98, and 128 and 34.99 (it would be really helpful to know thanks) show work

SpyIntel [72]

Answer:

The unit costs are $0.77, $0.62 and $0.27 respectively.

Step-by-step explanation:

The unit price is simply the cost of the items divided by the amount of the items that are included. So, just take the cost and divide it.

$12.29/16 = $0.77 per unit

$19.98/32 = $0.62 per unit

$34.99/128 = $0.27 per unit

3 0

4 years ago

(5-(-4)^2)^2)

stepladder [879]

Answer:

121

Step-by-step explanation:

You are missing a parentheses

Assuming you just mean to close the parentheses

((5-(-4)^2)^2)

The first step is to complete the inside parentheses

PEMDAS

(5-(-4)^2)

Do the exponents first

(5-(16))

-11

Put this in the equation for (5-(-4)^2)

(-11) ^2

121

6 0

3 years ago

2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA

professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

$A=45e^{-0.0045(t)}$

a) To find the initial amount of this substance

At t=0, we get

$A=45e^{-0.0045(0)}$ $A=45e^0$

We know that e^0=1 ( anything to the power zero is 1)

we get,

$A=45$

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

$\frac{45}{2}=45e^{-0.0045(t)}$

$\frac{1}{2}=e^{-0.0045(t)}$

Taking natural logarithm on both sides we get,

$\ln (\frac{1}{2})=-0.0045(t)^{}$ $(-1)\ln (\frac{1}{2})=0.0045(t)$ $\ln (\frac{1}{2})^{-1}=0.0045(t)$ $\ln (2)=0.0045(t)$ $0.6931=0.0045(t)$ $t=\frac{0.6931}{0.0045}$ $t=154.02$

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

$A=45e^{-0.0045(2500)}$ $A=45e^{-11.25}$ $A=45\times0.000013=0.000585$ $A=0.000585$

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0

1 year ago

PL has endpoints P(4, −6) and L(−2, 1). The segment is translated using the mapping (x, y) → (x 5, y). What are the coordinates

cestrela7 [59]

The coordinates of P' is (9, -6) and L' is (3, -1).

<h2>Given that</h2>

PL has endpoints P(4, −6) and L(−2, 1).

The segment is translated using the mapping (x, y) → (x + 5, y).

<h3>We have to determine</h3>

What are the coordinates of P’ and L’?

<h3>According to the question</h3>

PL has endpoints P(4, −6) and L(−2, 1).

The segment is translated using the mapping (x, y) → (x + 5, y).

The coordinates of point P after translation using mapping is,

$\rm P(x, \ y) - P'(x+5, y)\\
\\
P(4, -6) - P'(4+5, \ -6)\\
\\
P(4, -6) - P'(9, -6)\\$

And the coordinates of point L after translation using mapping is,

$\rm L(x, \ y) - L'(x+5, y)\\\\L(-2, 1) - L'(-2+5, \ -1)\\\\L(4, -6) - L'(3, -1)\\$

Hence, The coordinates of P' is (9, -6) and L' is (3, -1).

To know more about Translation click the link given below.

brainly.com/question/26298109

8 0

3 years ago

Read 2 more answers

What is the probability to get a 5 or an odd number when you roll a die

8090 [49]

Answer:

50%

Step-by-step explanation:

6 numbers on a die, 3 of them are odd.

3/6=1/2=50%

6 0

3 years ago

Read 2 more answers