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Drupady [299]
3 years ago
9

Adding and subtracting With Scientific notationPlease help

Mathematics
1 answer:
Tom [10]3 years ago
4 0

Answer:

0.131

Step-by-step explanation:

10^-2=0.01 so 0.01+6=0.06

0.06+0.071=0.131

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What is the result when 6x^2-13x+12is subtracted =3x^2+6x+7
iragen [17]

Answer:

The answer is 3x²-7x+19

5 0
3 years ago
Please help me solve this priblem
Over [174]
It would be c. 12 inches

H = V/lw

The Length * Width = 450
and the volume is 5400
So 5400/450 = 12

Hope that helps!
5 0
3 years ago
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How many QUADRANT do we have in mathematics.​
kotegsom [21]

Answer:

4

Step-by-step explanation:

There are four Quadrants in Mathematics. Counting from the right to left, to left, then right, we can tell which quadrant we are in.

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2 years ago
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Jody practiced a piano piece for 500 seconds bill practiced a piano piece for 8 minutes who practiced longer explain
Mrac [35]

Answer:

Jody

Step-by-step explanation:

You can either convert 500 seconds to minutes or 8 minutes to seconds to compare. I'll do both.

There is 60 seconds in a minute. To find the total minutes of 500 seconds, divide 500 by 60 → 8.3, which means that Jody practiced for 8.3 minutes.

To find the total seconds of 8 minutes, multiply 60 seconds per minute by 8 minutes → 60 * 8 = 480 seconds which means that Bill practiced for 480 seconds.

Now you can compare. Jody practiced for 500 seconds, or 8.3 minutes. Bill practiced for 480 seconds, or 8 minutes. Jody practiced longer.

7 0
3 years ago
50PTS!<br> Describe the vertical asymptotes and holes for the graph of y = x-5/x^2 -1
Diano4ka-milaya [45]
Ok

first of all, for q(x)/p(x)
if the degree of q(x) is less than the degree of p(x),then the horizontal assemtote is 0

then simplify
any factors you factored out is now a hole, remember them

to find the vertical assemtotes of a function, set the SIMPLIFIED denomenator equal to 0 and solve

so

y=(x-5)/(x^2-1)
q(x)<p(x)
horizontal assemtote is y=0

no factors to simplify so no holes

set denomenator to 0 to find vertical assemtote
x^2-1=0
(x-1)(x+1)=0
x-1=0
x=1

x+1=0
x=-1

the horizontal assemtotes are x=1 and -1
3 0
3 years ago
Read 2 more answers
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