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3 years ago

Adding and subtracting With Scientific notationPlease help

Mathematics

1 answer:

Tom [10]3 years ago

4 0

Answer:

0.131

Step-by-step explanation:

10^-2=0.01 so 0.01+6=0.06

0.06+0.071=0.131

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describe the steps you used to solve the equation and find the amount of carries allowance. linear equation: 1/4a+1/3a+8=22

vlabodo [156]

1/4a + 1/3a +8 =22

1st step add like terms:

1/4a +1/3a = 3/12a +4/12a = 7/12a

7/12a +8 =22

2nd step subtract 8 from each side:

7/12a = 14

3rd step divide both sides by 7/12 to get a:

a = 14 / 7/12

a = 24

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3 years ago

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Which three angle measures can be used to make ABC?

solong [7]

Answer: B: 41, C: 68, D: 71.

Step-by-step explanation: A triangle's angles have to add up to 180 degrees for it to be considered a triangle. If you were to add up 71, 41, and 68, then it would equal 180 degrees. This means that out of all the other measurements, these are the three possible angle measures that can be used to make a triangle.

(I figured this out by taking 3 random sides from the list there and adding them up to see if they equal 180.)

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2 years ago

Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real

hoa [83]

Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

Let's compare all the given equation to it and , find discriminant.

1. a=2, b= -7, c=-9

$b^2-4ac=(-7)^2-4(2)(-9)=49+72>0$

So it has 2 real number solutions.

2. a=1, b=-4, c=4

$b^2-4ac=(-4)^2-4(1)(4)=16-16=0$

So it has only 1 real number solution.

3. a=4, b=-3, c=-1

$b^2-4ac=(-3)^2-4(4)(-1)=9+16=25>0$

So it has 2 real number solutions.

4. a=1, b=-2, c=-8

$b^2-4ac=(-2)^2-4(1)(-8)=4+32=36>0$

So it has 2 real number solutions.

5. a=3, b=5, c=3

$b^2-4ac=(5)^2-4(3)(3)=25-36=-9$

Thus it does not has real solutions.

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3 years ago

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Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of

Alex17521 [72]

Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

$2(L+x)=16 \\ \\ \Rightarrow L+x=8 \\ \\ \Rightarrow x=8-L$

Thus, if the length of one of the side is x, the length of the other side is 8 - L.

Hence, the area of the rectangle in terms of L is given by

$L(8 - L) = 8L-L^2$

Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

Hence the domain of the area are the set of values between 0 and 8 not inclusive.

Therefore,

$dom(Area)=0\ \textless \ L\ \textless \ 8 \ or \ (0, 8)$

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3 years ago

The difference of 22 and a number is -8 A.14 B.30 C.-30 D.-14

DIA [1.3K]

Answer:

B. 30

Step-by-step explanation:

the equation looks like 22 - x = -8 and 22 - 30 is negative 8

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3 years ago

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