Answer:
Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.
Step-by-step explanation:
Given:
In Δ PQT
PQ = 30 ft
QT = 28 ft
TP = 20 ft
In Δ QRS
QR = 15 ft
RS = 14 ft
SQ = 10 ft
To Prove:
Δ PQT ~ Δ QRS
Proof:
First we consider the ratio of the sides
..............( 1 )
..............( 2 )
..............( 3 )
So By equation ( 1 ), ( 2 ) and ( 3 ) we get
Now in Δ PQT and Δ QRS we have
Which are corresponding sides of a similar triangle in proportion.
∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved
We can get rid of the parentheses so it looks like this:
3x + 24x + 8.
Simplify:
27x + 8
Answer:
The proportion of the offspring from the cross PpRr × PpRr that are expected to have white flowers and wrinkled seeds is 1/16 or 6.25%.
Step-by-step explanation:
The uppercase letter represents the dominant allele, while the lowercase represents the recessive allele. The dominant allele determines the phenotype (observable trait) when it is present.
When you cross heterozygous individuals for each trait, each individual of the offspring has the probability of 1/6 of each combination of four alleles (two for each trait). Because the dominant allele determines the phenotype when it is present, the probability of dominant phenotypes is higher than recessive phenotypes.
Proportions of each phenotype in the offspring from the cross PpRr × PpRr are:
Purple flowers with round seeds: 9/16
Purple flowers with wrinkled seeds: 3/16
White flowers with round seeds: 3/16
White flowers with wrinkled seeds: 1/16
The proportion of individuals with white flowers and wrinkled seeds is the lowest because they are homozygous recessive for both traits.
Answer:
x = 1/3
Step-by-step explanation:
1 = 1/x -2
add 2 to both sides
3 = 1/x
x = 1/3
