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3 years ago

Any suggestions or answers

Mathematics

1 answer:

OLEGan [10]3 years ago

5 0

2nd answer.

any pts in the shaded region satisfies your simultaneous equation.

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In triangle XYZ. the measurements of angle X and angle Y are 45° Which is the longest side of the triangle

ipn [44]

Answer:

the side XY

Step-by-step explanation:

we know 2 angles in a triangle. but are 45 degrees.

that means the third angle Z is 180-45-45 = 90 degrees.

the side opposite of the largest angle is the longest side.

opposite of Z is the side XY.

6 0

2 years ago

For each sequence find the first 4 terms and the 10th term

jolli1 [7]

Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:

a) 1 (1st term) + 5 = 6

2 (2nd term) + 5 = 7

3 (3rd term) + 5 = 8

4 (4th term) + 5 = 9

10 (10th term) + 5 = 15

And so on for b (not going to keep writing the term, I’m sure you get that by now.

b) 2(1) - 1 = (2x1) - 1 = 1

2(2) - 1 = (2x2) - 1 = 3

2(3) - 1 = (2x3) - 1 = 5

2(4) - 1 = (2x4) - 1 = 7

2(10) - 1 = (2x10) - 1 = 19

Hope this helps :)

4 0

3 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

8 0

2 years ago

Tell whether the lines through the given points are parallel, perpendicular, or neither. (-3,1), (1,9), (-2-9), (-1,-7)

Brrunno [24]

Answer:

parallel

Step-by-step explanation:

all the details are in the attached picture.

4 0

3 years ago

Help asap I will give u huge amount of brainly points

Minchanka [31]

Answer:

$\boxed{\sf -\dfrac{5}{8}}$

Use BODMAS rule,

where:

brackets
order
division
multiplication
addition
subtraction

Given expression:

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{4} \right)^2]$

simplify exponent

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{16} \right)]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{14}{16}]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{7}{8}]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{32}{8} -\(\dfrac{7}{8}]$

$\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{25}{8}]$

multiply fractions

$\rightarrow \sf -\dfrac{25}{40}$

$\rightarrow \sf -\dfrac{5}{8}$

8 0

1 year ago

Read 2 more answers