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Delvig [45]
3 years ago
12

Any suggestions or answers

Mathematics
1 answer:
OLEGan [10]3 years ago
5 0
2nd answer.

any pts in the shaded region satisfies your simultaneous equation.
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Step-by-step explanation:

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Sqrt 6^2 + 8^2 jdjdjsns
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Step-by-step explanation:

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2 years ago
The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot
Romashka [77]

Answer:

<u>Shelter A</u>

Step-by-step explanation:

For Shelter A: the whiskers range from 8 to 30

so, the minimum weight of Shelter A is 8 pounds.

For For Shelter B: the whiskers range from 10 to 28

so, the minimum weight of Shelter B is 10 pounds.

<u> Which animal shelter has the dog that weighs the least? </u>

<u>The answer is: Shelter A</u>

Note: whiskers are plotted are from the minimum to Q1 and from Q2 to the max.

See the attached figure.

4 0
3 years ago
Read 2 more answers
Which relationship has a zero slope? A two column table with five rows. The first column, x, has the entries, negative 3, negati
Anon25 [30]

Answer:

The one in the table on the left

Note that for the given values of x all of the y values are 2

This indicates a horizontal line, parallel to the x- axis with a slope of zero.

The equation of the line is y = c where c is the value of the y- coordinates the line passes through, in this case 2, thus

y = 2 is the equation of the line with zero slopeation

one of them is an undefined slope the other is a positive slope (Neither of them are a zero slope)

5 0
3 years ago
Read 2 more answers
A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school
Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.                                                    

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.15

P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15  

= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15  

=P( z \leq \displaystyle\frac{x - 225}{43})=0.85  

Calculation the value from standard normal z table, we have,  

P(z < 1.036) = 0.85

\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

3 0
3 years ago
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