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3 years ago

Any suggestions or answers

Mathematics

1 answer:

OLEGan [10]3 years ago

5 0

2nd answer.

any pts in the shaded region satisfies your simultaneous equation.

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3 years ago

Sqrt 6^2 + 8^2 jdjdjsns

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2 years ago

The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot

Romashka [77]

Answer:

Shelter A

Step-by-step explanation:

For Shelter A: the whiskers range from 8 to 30

so, the minimum weight of Shelter A is 8 pounds.

For For Shelter B: the whiskers range from 10 to 28

so, the minimum weight of Shelter B is 10 pounds.

Which animal shelter has the dog that weighs the least?

The answer is: Shelter A

Note: whiskers are plotted are from the minimum to Q1 and from Q2 to the max.

See the attached figure.

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3 years ago

Read 2 more answers

Which relationship has a zero slope? A two column table with five rows. The first column, x, has the entries, negative 3, negati

Anon25 [30]

Answer:

The one in the table on the left

Note that for the given values of x all of the y values are 2

This indicates a horizontal line, parallel to the x- axis with a slope of zero.

The equation of the line is y = c where c is the value of the y- coordinates the line passes through, in this case 2, thus

y = 2 is the equation of the line with zero slopeation

one of them is an undefined slope the other is a positive slope (Neither of them are a zero slope)

5 0

3 years ago

Read 2 more answers

A college football coach has decided to recruit only the heaviest 15% of high school football players. He knows that high school

Alla [95]

Answer:

The coach should start recruiting players with weight 269.55 pounds or more.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 225 pounds

Standard Deviation, σ = 43 pounds

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.15

$P( X > x) = P( z > \displaystyle\frac{x - 225}{43})=0.15$

$= 1 -P( z \leq \displaystyle\frac{x - 225}{43})=0.15$

$=P( z \leq \displaystyle\frac{x - 225}{43})=0.85$

Calculation the value from standard normal z table, we have,

$P(z < 1.036) = 0.85$

$\displaystyle\frac{x - 225}{43} = 1.036\\\\x = 269.548 \approx 269.55$

Thus, the coach should start recruiting players with weight 269.55 pounds or more.

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3 years ago