It would be B.
The 6 and 9 look the same up side down and so do the HOH
In fact, none of the above. It is 2(60h+m).
Answer:
B. 
Step-by-step explanation:
Given:
The given triangle is an isosceles right angled triangle with the legs equal to 6 cm each and the hypotenuse is 'x' cm.
Applying Pythagoras theorem which states that the square of the hypotenuse is equal to the sum of the squares of the other two sides. Therefore,
Therefore, the length of the hypotenuse is 
cm.
Hence, the option B is the correct one.
Answer:
x = 1 +√5
Step-by-step explanation:
There are different formulas for the area of a triangle available, depending on the given information.
<h3>Formulas</h3>
When two sides and the angle between them are given, the relevant area formula is ...
Area = 1/2(ab)sin(C)
When the base and height of a triangle are given, the relevant area formula is ...
Area = 1/2bh
<h3>Equal Areas</h3>
The problem statement tells us the two triangles shown have equal areas. That means the two formulas will give the same result.
Area from angle = Area from base/height
1/2(x·x)sin(30°) = 1/2(x-2)(x+1)
x² = 2(x² -x -2) . . . . . . . . . . . use sin(30°) = 1/2, multiply by 4
x² -2x -4 = 0 . . . . . . . . subtract x², eliminate parentheses
(x -1)² = 5 . . . . . . . . . add 4+1 to complete the square
<h3>Value of x</h3>
x = 1 ± √5 . . . . . . take the square root, add 1
The value of x must be greater than 2 in order for the triangle side lengths to be positive. (x-2 > 0) This means x = 1-√5 is an extraneous solution.
The value of x is 1 +√5.
