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denis23 [38]
4 years ago
14

Name three requirements contained in the specifications regarding material

Mathematics
2 answers:
soldi70 [24.7K]4 years ago
4 0
What specifications? Please give me more information.
Daniel [21]4 years ago
4 0
Construction specifications, performance specifications, and  <span>Proprietary Specifications</span>
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The following frequency table relates the weekly sales of bicycles at a given store over a 42-week period.
7nadin3 [17]

Answer:

14

Step-by-step explanation:


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3 years ago
What is the equation in vertex form of a
gulaghasi [49]

Answer:

B.

Step-by-step explanation:

Vertex with (2,4) means that the equation will have:

y=a(x-2)^2 + 4

Open downwards means that the a will be negative:

so: y = -a (x-2)^2 + 4

Stretched by a factor of 3 means that the a=3

So if we combine all of these, we will get the equation:

y = -3 (x-2)^2 + 4

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What is the answer to this problem
dalvyx [7]

Answer:

8.65.

Step-by-step explanation:

B is halfway between 8.6 and 8.7.

Therefore B is 8.65.

6 0
3 years ago
okay everybody ive been answer algebra and there all good answer but nobody seems to say thank you or nothing when there looking
mylen [45]

Answer:

I hate when people do that so I always say thanks when people give legit answers

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243, how many grams will remain after 12 days?
quester [9]

Answer:

C.4.18g

The amount will remain after 12 days is 4.18 g

Step-by-step explanation:

we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

where

h is half life time

t is time in days

Po is initial quantity

P(t) is the quantity after t days

we are given

Curium-243 has a half-life of 28.5 days

h=28.5

In a sample of 5.6 grams of curium-243

so,

P_0=5.6

now, we can plug values

P(t)=5.6(\frac{1}{2})^{\frac{t}{28.5} }

now, we can plug t=12

P(12)=5.6(\frac{1}{2})^{\frac{12}{28.5} }

P(12)=4.18253

So,

The amount will remain after 12 days is 4.18 g

3 0
4 years ago
Read 2 more answers
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