You must do 6 to the second power then plug in 3 for M which gives you 36/2(3), multiply 2 times 3 to get 6 then divide. Your answer is 6.
First

Then

To get

So...


To get y = 4.


Next

Finally

Therefore our solutions are y = 4, x = 3
Answer:
bearing of A from C is - 65.24°
the distance |BC| is 187.84 m
Step-by-step explanation:
given data
girl walks AB = 285 m (side c)
bearing angle B = 78°
girl walks AC = 307 m (side a)
solution
we use here the Cosine Law for getting side b that is
ac² = ab² + bc² - 2 × ab × cos(B) ...............1
307² = 285² + x² - 2 × 285 cos(78)
x = 187.84 m
and
now we get here angle θ , the bearing from A to C get by law of sines
sin (θ) =
sin (θ) = 0.5985
θ = 36.76°
and as we get here angle BAC that is
angle BCA = 180 - ( 36.76° + 78° )
angle BCA = 65.24°
and here negative bearing of A from C so - 65.24°
Y-4=1/4*(x-1)²
<span>y=1/4(x-1)²+4
</span><span>the parabola y=1/4x2 with vertex at the point (1;4),the branches up,x=1 is the axis of symmetry intersects the axis of the OY at the point (0;4 1/4)
</span>
I dont know that language