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3 years ago

A student inscribes a triangle within a semicircle what is the measure of MMO

Mathematics

2 answers:

ExtremeBDS [4]3 years ago

8 0

Solution:

Must keep in mind: Angle in a Semicircle is a right Angle.

If one Side of Triangle is along the Diameter and the other two sides intersect at a point on the circle, then angle between those two sides which intersect at a point on the circle measures 90°.

Measure of that angle will be of 90°.

Option D: 90 degrees

Maru [420]3 years ago

3 0

The answer is 90 degrees.

I hope this helped!

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Write an explanation of how to change a number in decimal notation to scientific notation.

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Answer:

Move the decimal place to the left. Determine the exponent (number of times you moved the decimaal place). Plug it into (N x 10^a)

Step-by-step explanation:

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3 years ago

The general term for the sequence 2, 4, 8, 16, 32, . . . is<br><br> n + 2<br> 2n<br> 2^n

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3 years ago

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alexandr1967 [171]

Answer:

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

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3 years ago

Goofy Golf ticket prices for kids under 12 years of age increased from $4.00 to $6.00 this year. What is the percent of increase

Dmitry [639]

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3 years ago

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Xavier, Yvonne, and Zelda each try independently to solve a problem. If their individual probabilities for success are 1/4, 1/2

siniylev [52]

<u>Answer:</u> The probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

<u>Step-by-step explanation:</u>

We are given:

Probability of success of Xavier, $P(S)_{Xavier}=\frac{1}{4}$

Probability of failure of Xavier, $P(F)_{Xavier}=1-\frac{1}{4}=\frac{3}{4}$

Probability of success of Yvonne, $P(S)_{Yvonne}=\frac{1}{2}$

Probability of failure of Yvonne, $P(F)_{Yvonne}=1-\frac{1}{2}=\frac{1}{2}$

Probability of success of Zelda, $P(S)_{Zelda}=\frac{5}{8}$

Probability of failure of Zelda, $P(F)_{Zelda}=1-\frac{5}{8}=\frac{3}{8}$

We need to calculate:

The probability that Xavier and Yvonne can solve the problem but Zelda cannot, we use:

$P(S)_{Xavier}\times P(S)_{Yvonne}\times P(F)_{Zelda}=\frac{1}{4}\times \frac{1}{2}\times \frac{3}{8}=\frac{3}{64}$

Hence, the probability that Xavier and Yvonne can solve a problem but Zelda cannot is $\frac{3}{64}$

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3 years ago