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harina [27]
2 years ago
14

“Find the x and y intercepts of the line.”

Mathematics
1 answer:
podryga [215]2 years ago
7 0

The y intercept is -3 the x intercept is -.6 repeating





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I purchase x pizzas, y 12-packs of soda, and z cupcakes for a party. If each pizza costs $7.50, each 12-packs of soda costs $3.2
svetlana [45]

Answer:

t=7.50x+0.75z+3.25y

8 0
3 years ago
What does -2(3x-4)=8 mean??
Tom [10]
-2(3x-4)=8
-6x + 8 = 8
-6x = 0
x = 0
6 0
2 years ago
What are solutions to the equation below x^2 +3x-18=0
Ivenika [448]

x^2 +3x-18=0\\ x^2-3x+6x-18=0\\ x(x-3)+6(x-3)=0\\ (x+6)(x-3)=0\\ x=-6 \vee x=3

5 0
3 years ago
Read 2 more answers
Os
algol [13]

Answer:

\boxed{\sf{4}}}

Step-by-step explanation:

Use a slope form.

<u>Slope:</u>

\sf{\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{rise}{run}  }

y₂ = (17)

y₁ = (1)

x₂ = (2)

x₁ = (-2)

Then, rewrite the problem.

Solve.

\sf{\dfrac{17-1}{2-(-2)}=\dfrac{16}{4}=\dfrac{16\div4}{4\div4}=\dfrac{4}{1}=\boxed{\sf{4}    }

Therefore, the slope is 4, which is our answer.

I hope this helps you! Let me know if my answer is wrong or not.

5 0
2 years ago
The cosine of 23° is equivalent to the sine of what angle
Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

\cos(90^\circ-x)=\sin(x)

or

\sin(90^\circ-x)=\cos(x)

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0
2 years ago
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