You can square the whole problem to cancel out the square root. Might make things easier.
Answer:
Mon - Fri: 4 days 4*30 = 120 bars given away. 225 - 120 = 135 bars
Step-by-step explanation:
Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer:
Since the volume of the cone is bigger than the volume of the scoop, it won't spill.
Step-by-step explanation:
In order to calculate if the ice cream will spill we will need to calculate the volume on the ice cream scoop and the volume of the cone. If the volume of the scoop is bigger than the cone it will spill.
volume scoop = (4/3)*pi*r³ = (4/3)*pi*(2/2)³ = 4.1888 in³
volume cone = (pi*r²*h)/3 = [pi*(2/2)²*5]/3 = 5.236 in³
Since the volume of the cone is bigger than the volume of the scoop, it won't spill.
A rectangle has 2 triangle
∴ 25 feet² × 2 = 50 feet²