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kari74 [83]
3 years ago
9

What is the y-intercept of the equation of the line that is perpendicular to the line y =3/5x + 10 and passes through the point

(15, –5)? The equation of the line in slope-intercept form is y = -5/3x + .
Mathematics
2 answers:
vladimir1956 [14]3 years ago
4 0
The answe would be y=-5/3x+20
FrozenT [24]3 years ago
3 0

Answer:

Equation of the line in the slope-intercept form will be y=-\frac{5}{3}x+20

Step-by-step explanation:

An equation of the line perpendicular to y=\frac{3}{5}x+10 will be in the form of y = mx + c

Where m = slope of the line

c = y intercept of the line

From the property of the perpendicular line

m_{1}\times m_{2}=-1

where m_{1} and m_{2} are the slopes of the perpendicular lines.

If  m_{1} = \frac{3}{5}

then \frac{3}{5}\times m_{2}=-1

m_{2}=-\frac{5}{3}

So the equation will be y=-\frac{5}{3}x+c

This line passes through the point (15, -5)

(-5)=-\frac{5}{3}(15)+c

-5 = -25 + c

c = 25 - 5

c = 20

Finally the equation will be y=-\frac{5}{3}x+20

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Tina is saving to buy a notebook computer. She has two options. The first option is to put $500 away initially and save $10 ever
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Answer:

Tina would save the same amount using either option after 20 months.

With either option, Tina would save $700.

Step-by-step explanation:

This problem can be modeled by a first order equation:

Where Tina's saved money after n months is:

S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.

The first option is to put $500 away initially and save $10 every month, so:

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The second option is to put $100 away initially and save $30 every month, so:

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How much would she save with either option?

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S_{1}(20) = 500 + 10(20) = 500 + 200 = 700

With either option, Tina would save $700.

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