To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
3.3 % chance that will randomly pick tallest
Answer:
C. These lines are perpendicular
Step-by-step explanation:
Answer:
x = 5
Step-by-step explanation:
11 = 4x-9
20 = 4x
20/4 = 4x/4
5 = x
→ 3 ≠ 1 → A is eliminated.
→ 5 ≠
→ B is eliminated.
→ 2 = 2 → C satisfies the equation.
→ 10 ≠
→ D is eliminated.
→ -1 = -1 → E satisfies the equation.
→ 3 = 3 → F satisfies the equation.