The longest diagonal

Mathematics

1 answer:

Ratling [72]2 years ago

8 0

The diagonals are:
diagonal₁=2x+3y
diagonal₂=(x+8)+(2y+5)
We have to solve the following system of equations:
2x=3y
(x+8)=(2y+5)
We solve this system by substitution method:
2x=3y ⇒x=3y/2

(3y/2 +8)=2y+5
3y+16=4y+10
-y=-6
y=6

x=3y/2=3*6/2=9

we obtain the measure of the diagonals:
diagonal₁=2x+3y=2*9+3*6=18+18=36
diagonal₂=(x+8)+(2y+5)=(9+8)+(2*6+5)=17+17=34

Answer: The longest diagonal is 36 units.

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<h3>How to determine the number of groups?</h3>

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