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katen-ka-za [31]
3 years ago
9

The longest diagonal

Mathematics
1 answer:
Ratling [72]3 years ago
8 0
The diagonals are:
diagonal₁=2x+3y
diagonal₂=(x+8)+(2y+5)
We have to solve the following system of equations:
2x=3y
(x+8)=(2y+5)
We solve this system by substitution method:
2x=3y  ⇒x=3y/2

(3y/2 +8)=2y+5
3y+16=4y+10
-y=-6
y=6

x=3y/2=3*6/2=9

we obtain the measure of the diagonals:
diagonal₁=2x+3y=2*9+3*6=18+18=36
diagonal₂=(x+8)+(2y+5)=(9+8)+(2*6+5)=17+17=34

Answer: The longest diagonal is 36 units. 
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Solve the following problems. Remember that all reasoning must be explained, and all steps of math work must be shown!
iris [78.8K]

Answer to Question 1:

<OGE (also m˚) = 19˚

Step-by-step explanation:

We know that all the angles in a triangle add up to 180˚.

<u>Given:</u>

<EGO = 71˚

<OEG = 90˚ (the angle forms a right angle because line EG is perpendicular to point O)

<u>To Solve:</u>

⇒ Since we know two angles, we should know the third; and they all add up to 180˚. This can be written as:

71˚ + 90˚ + <OGE = 180˚

⇒ Solve for <OGE by simplifying:

161˚ + <OGE = 180˚

⇒ Subtract 161˚ from both sides to get:

161˚ − 161˚ + <OGE = 180˚ − 161˚

⇒ Isolate <OGE:

<OGE = 19˚

<u>Answer:</u> <OGE (also m˚) = 19˚

Answer:

<OAC (also x˚) = 50˚

<OCB (also y˚) = 90˚

Step-by-step explanation:

–<u>How to solve for <OCB (also y˚)</u>

Just by looking, you can already tell that <OCB equals 90˚ because it forms a right angle.

<u>Answer:</u> <OCB (also y˚) = 90˚

–<u>How to solve for <OAC (also x˚)</u>

<u>Given (and what we can already know):</u>

<AOC = 40˚

<OCA = 90˚

⇒ Reason: Line AB is a straight line and a straight line equals 180˚. We already know on side of the line because <OCB is 90˚, and so the other side, <OCA, should also be 90˚, since the both sides that make up the straight line equal 180˚ (90˚ + 90˚ = 180˚). You can also tell that <OCA forms a right angle in the triangle because line AB is perpendicular to point O, and right angles are 90˚.

<u>To Solve:</u>

⇒ Since we know two angles in the triangle, we should know the third; and they all add up to 180˚. This can be written as:

40˚ + 90˚ + <OAC = 180˚

⇒ Solve for <OAC by simplifying:

130˚ + <OAC = 180˚

⇒ Subtract 130˚ from both sides to get:

130˚ − 130˚ + <OAC = 180˚ − 130˚

⇒ Isolate <OAC:

<OAC = 50˚

<u>Answer:</u> <OAC (also x˚) = 50˚

I hope you understand and that this helps with your question! :)

3 0
2 years ago
a wheel has a diameter of 15cm. The wheel travels 50 metres. How many revolutions does the wheel complete?
TEA [102]

Answer:

106

Step-by-step explanation:

The diameter of the wheel is 15 cm or 0.15 m.

The circumference of the wheel is 0.15π m ≈ 0.47 m.

So the wheel moves 0.47 m with each revolution.

The wheel travels 50 m, so the number of revolutions is:

(50 m) / (0.47 m/rev) ≈ 106 revolutions.

8 0
2 years ago
Is the answer is b ? Help
PilotLPTM [1.2K]

Answer:

No, it is D.

Step-by-step explanation:

<em>It can not be A or C, because length can not be negative</em>

Because the y is the same, you only have to <em>count the distance of the x-axises</em>.

4 - (-3) is 7 units, which is D.

6 0
2 years ago
Need help with my homework 2 problems
Solnce55 [7]
4(x+2)  ,   2(2x+4)  ,  8+4x  ,   1/2(8x+16) are all the same as 4x+ 8.
5 0
2 years ago
Factorise (2t-7)²-(5t-4)² <br>with working pls​
sertanlavr [38]

Answer:

33+12t−21t^2

Step-by-step explanation:

(2t-7)²-(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².

4t^2−28t+49−(5t-4)²

Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².

4t^2−28t+49−(25t^2−40t+16)

To find the opposite of 25t^2

−40t+16, find the opposite of each term.

4t^2−28t+49−25t^2−40t+16

Combine 4t^2  and −25t^2  to get −21t^2.

−21t^2−28t+49+40t−16

Combine −28t and 40t to get 12t.

−21t^2+12t+49−16

Subtract 16 from 49 to get 33.

−21t^2+12t+33

Swap terms to the left side.

33+12t−21t^2

I hope this helped!

5 0
3 years ago
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