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ioda
3 years ago
14

an employee has an annual salary of $48,700. they receive $1,530 in health insurance and $2,810 in paid time off per year. they

drive their personal vehicle for work which costs them $500 per month, but the company reimburses them $0.53 per mile for the total work miles driven. if the employee drives 9,000 miles for work for the year, what will be their total employment compensation?
Mathematics
2 answers:
Tema [17]3 years ago
7 0
Annual salary = 48, 700
Health Insurance= 1530
Paid time off= 2810

Employment compensation= Annual salary+Health Insurance + Paid time off
                                           = 58700+1530+2810
                                            = 53,040
Expenses= Vehicle cost per year-  reimbursement
                 =(500*12)-0.53*9000
=6000-4770
=1230 per year
Total compensation= 53,040-1230
                               = 51810 dollars

Anna [14]3 years ago
6 0
Compensation for the year:$51,810(deducting vehicle expense)

An employee makes 48,700+1,530(health insurance)+2,810(paid time)=

53,040.  Also they receive 0.53 per mile x 9,000 miles=4,770

53,040 +4,770=57,810(employment compensation)

Personal work vehicle expense: 500 x 12 months=6,000

57,810 - 6,000= 51,810
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Answer:

a = \sqrt{7}

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

<em>Suppose ABC is a right triangle with sides​ a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4</em>.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

a^2+b^2=c^2

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a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7

so a = \sqrt{7}

We know that tangent relates opposite side of a right triangle with adjacent side.

\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}

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