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Over [174]
3 years ago
6

Finf the exact value of sin A and cos A where a = 9 and b = 10 and <c is a right angle

Mathematics
2 answers:
Katyanochek1 [597]3 years ago
8 0
To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2. 
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)

Artemon [7]3 years ago
3 0

Answer:

sin A = 0.6666666667 ≈ 0.67

cos A = 0.7407407407  ≈ 0.74

Step-by-step explanation:

The triangle above is a right angle triangle . Angle C is the angle 90°. we can use the cosine law for triangle to solve for side c.

c² = a² + b² - 2ab.cos(C)

a = 9

b = 10

C = 90°

c² = 9² + 10² - 2 × 9 × 10 cos( 90)

c² = 81 + 100 - 180 × 0

c² = 181

c = √181

c = 13.45362405  ≈ 13.5

Using sine rule

a/sin A = b/sin B = c/sin C

a = 9

b = 10

c = 13.5

C = 90°

9/sin A = 13.5/sin 90°

13.5 sin A = 9 × sin 90°

13.5 sin A = 9

sin A = 9/13.5

sin A = 0.6666666667

Use SOHCAHTOA principle to find cos A

cos A = b/c

cos A =  10/13.5

cos A = 0.7407407407

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the highest f(x) value on the table is at -4 on the x column

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3 years ago
What does the graph of lnx look like?
qwelly [4]
This is what the graph of in(x) looks like

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Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),
butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

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