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Archy [21]
3 years ago
12

Use the method of completing the square to write the equation of the given parabola in this form:

Mathematics
1 answer:
Fudgin [204]3 years ago
4 0
This is a very challenging equation but I'll try my best!

<span>y-k=a(x-h)^2
Vertex(1,1) ----\ \textgreater \  y-1=a(x-1)^2 &#10;contains~ the ~point (0,-3) &#10;&#10;----\ \textgreater \  1-1=a(0-,-3)^2 &#10;&#10;----\ \textgreater \  1=-2a &#10;&#10;----\ \textgreater \  a=1/-2&#10;&#10;Equation: Y-1=1/-2(x-2)^2
</span>
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3(2x + 7) - 2 (x + 5)
olga55 [171]

Answer:

Step-by-step explanation:

3(2x + 7) - 2 (x + 5)

need to distibute

5x+10-2x+3

combine like terms

3x+13

divide

x=4.3

5 0
3 years ago
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The net of a square pyramid is shown below:
torisob [31]

28 is the correct answer.


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Picture of problem below NO LINKS
iragen [17]

Answer:

600$

Step-by-step explanation:

I think this is right

5 0
3 years ago
For the given expression identify the terms like terms coefficient and constant terms then simplify the expression -8c+-c+1
boyakko [2]

Answer:

The simplified expression is : -9c +1

Step-by-step explanation:

The like terms are -8c and -c

The constant term is 1

The simplified expression is :

-8c + -c + 1 = -9c +1

6 0
3 years ago
If an object is propelled upward from a height of s feet at an initial velocity of v feet per​ second, then its height h after t
Sergio039 [100]

From the given information we can write the equation:

-16t^2 +96t + 4 = 112

-16t^2 + 96t + 4 - 112 = 0

-16t^2 + 96t - 108 = 0

simplify, change the signs, divide by -4

4t^2 - 24t + 27 = 0


You can use the qudratic formula but this will factor to

(2t-3)(2t-9) = 0

Two solutions

t = 3/2

t = 1.5 seconds at 112 ft on the way up

and

t = 9/2

t = 4.5 seconds at 112 ft on the way back down

Graphically, (green line is 112 ft)


5 0
3 years ago
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