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Gelneren [198K]
3 years ago
10

1. Star Inc. has Year 1 revenues of $80 million, net income of $9 million, assets of $65 million, and equity of $40 million, as

well as Year 2 revenues of $87 million, net income of $22 million, assets of $70 million, and equity of $50 million. Calculate Star’s return on equity (ROE) for each year based on the DuPont method and compare it with a direct ROE measure. Next, explain why the firm’s ROE changed between Year 1 and Year 2.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
4 0
90000 because it changes when 7x is inside
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The sum of three consecutive odd numbers in 177. What is the largest of the three numbers?
Vikentia [17]

Answer:

1st odd  = 57

2nd odd  = 59

3rd odd  = 61

Step-by-step explanation:

Suppose the numbers to be:

1st odd = x -2

2nd odd = x

3rd odd = x +2

Now according to given conditions:

1st odd + 2nd odd + 3rd odd = 177

x - 2 + x +x + 2 = 177

By add -2 and + 2 will be cancelled

Adding all x

3x = 177

Dividing both sides by 3 we get

x = 177 / 3

x = 59

Now putting x = 59 to get three consecutive odds:

1st odd = x -2 = 59 - 2 = 57

2nd odd = x = 59

3rd odd = x +2 = 59 + 2 = 61

Proof:

1st odd + 2nd odd + 3rd odd = 177

57 + 59 + 61 = 177

177 = 177

hence proved

I hope it will help you!

6 0
3 years ago
Read 2 more answers
Help please?<br> Also explain as much as you can
Natalija [7]
X^3 = 16
x^3 = 4^2

x = ∛4^2
x = 4^2/3

answer
B. 4^2/3

------------------
x^5 = 16
x^5 = 2^4
x = 2^4/5

answer
D. x = 2^4/5

5 0
3 years ago
A large tank is filled to capacity with 600 gallons of pure water. brine containing 4 pounds of salt per gallon is pumped into t
nignag [31]
If A(t) is the amount of salt in the tank at time t, then the rate at which the amount of salt in the tank changes is given by

\dfrac{\mathrm dA(t)}{\mathrm dt}=\dfrac{4\text{ lbs}}{1\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}-\dfrac{A(t)\text{ lbs}}{600\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}
\dfrac{\mathrm dA}{\mathrm dt}=24\dfrac{\text{lb}}{\text{min}}-\dfrac{A(t)}{100}\dfrac{\text{lb}}{\text{min}}

Let's drop the units for now. We have

\dfrac{\mathrm dA(t)}{\mathrm dt}+\dfrac{A(t)}{100}=24
e^{t/100}\dfrac{\mathrm dA(t)}{\mathrm dt}+e^{t/100}\dfrac{A(t)}{100}=24e^{t/100}
\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/100}A(t)\right]=24e^{t/100}
e^{t/100}A(t)=\displaystyle24\int e^{t/100}\,\mathrm dt
e^{t/100}A(t)=2400e^{t/100}+C
A(t)=2400+Ce^{-t/100}

We're given that the water is pure at the start, so A(0)=0, giving

A(0)=0=2400+Ce^{-0/100}\implies C=-2400

So the amount of salt in the tank (in lbs) at time t is

A(t)=2400\left(1-e^{-t/100}\right)
4 0
3 years ago
Enter the decimal equivalent of 6/8​
ikadub [295]

Answer:

.75

Step-by-step explanation:

6/8 can be simplified to 3/4, if that helps.

3 0
3 years ago
According to the graph what is the value of the constant in the equation below?<br> Answer:0.5
worty [1.4K]
Constant=2 you can try this method with the other points

6 0
3 years ago
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