Answer:
No.. I think they are made up of nucleotides
Explanation:
I think it might be C, as the genome is specific to an individual, so the gene pool is that for the population, I suppose.
Answer: No
Explanation: (in plant cells) a plate that develops at the midpoint between the two groups of chromosomes in a dividing cell and that is involved in forming the wall between the two new daughter cells.
Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
E. two of the above are correct
Explanation:
Fermentation reactions are processes that occur without the presence of oxygen and promote the release of energy (ATP) anaerobically. For these reactions to occur, glycolysis and reduction of pyruvate must occur.
These reactions allow the regeneration of NAD + that is necessary for the breakdown of glucose during the process called glycolysis, which is primarily responsible for the production of ATP. NAD + is regenerated from NADH.
With that, we can conclude that the correct options are:
B. often require the reactions of glycolysis to provide energy as ATP
C. supply NAD for the oxidation of glucose
