Answer with Step-by-step explanation:
We are given that two events A and B are mutually exclusive.




a.For mutually exclusive events,

Therefore, event A can not occurred if event B has occurred because two events can not occur together.
Answer:No, by definition mutually exclusive events cannot occur together.
b.When two events are independent
Then , 

If two events are mutually exclusive then

Then , 
Therefore, 
Hence, we can concluded that events A and B are not independent if they are mutually exclusive.
Answer:Yes, 
Step-by-step explanation:

Decreased amount = 80 * 0.65 = 52
So, new amount = 80 - 52 = 28
In short, Your Answer would be 28
Hope this helps!
<h3>
Answer: -10 and -40</h3>
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Explanation:
a = 200 = first term
d = -30 = common difference
Tn = nth term
Tn = a + d(n-1)
Tn = 200 + (-30)(n-1)
Tn = 200 - 30n + 30
Tn = -30n + 230
Set Tn less than 0 and isolate n
Tn < 0
-30n + 230 < 0
230 < 30n
30n > 230
n > 230/30
n > 7.667 approximately
Rounding up to the nearest whole number gets us 
So Tn starts to turn negative when n = 8
We can see that,
Tn = -30n + 230
T7 = -30*7 + 230
T7 = 20
and
Tn = -30n + 230
T8 = -30*8 + 230
T8 = -10 is the 8th term
and lastly
Tn = -30n + 230
T9 = -30*9 + 230
T9 = -40 is the ninth term
Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.
Answer:
y = -2/3x - 11/3
Step-by-step explanation: