Answer:
plz write the question correctly
Answer:
Step-by-step explanation:
Not near enough information to know.
I ASSUME that the pool is surrounded by a walkway of constant width (w = 2 ft, from comments)
The pool shape is important as well. No mention of the shape
If the pool is circular and the walkway is 3 ft wide
the fence encloses a diameter of 110/π = 35 ft
so the diameter of the pool would be 35 - 2(3) = 29 ft.
POOL IS RECTANGULAR from comments
If the pool is square and the walkway is 2 ft wide, each side of the fence is
110 / 4 = 27.5 ft and the pool would be 27.5 - 2(2) = 23.5 ft on a side.
There are an infinite number of rectangular width and length dimensions and walkway dimensions which would result in a fence length of 110 ft.
Edit from comments
Still an infinite number of rectangular length an width dimensions for a pool with a 2 ft wide walkway around it.
Let's say that we are told the pool is 12 ft wide with 2 ft walkway.
Let L be the pool length
110 = 2(12 + 2(2)) + 2(L + 2(2))
110 = 32 + 2L + 8
70 = 2L
L = 35 ft
Answer:
The answer is (g°f)(-1) = 27
Step-by-step explanation:
* (g°f)(1) ⇒ means make the domain of g is the range of f
- At first find the value of f(-1)
- Take the answer and substitute it as the value of x for g
- So the range of f is the domain of g
∵ f(x) = 4x + 7
∵ The domain of f = -1 ⇒ x is the domain
∴ f(-1) = 4(-1) + 7 = -4 + 7 = 3 ⇒ f(-1) is the range
∵ g(x) = x³
∵ x = f(-1) = 3 ⇒ the domain of g
∴ g(3) = 3³ = 27 ⇒ the range of g
* (g°f)(-1) = 27
Since the blue marbles are 11 and the red marbles are 7 you start will the red marbles first because the question say red marbles to blue marbles
7:11
