The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Answer:
x=15is your answer
Step-by-step explanation:
8x=120 vertically opposite angle
x=120/8=15
In 22, you're looking for the vertical height of the triangle. You're given the angle opposite the side you want to find (which I'll call
) and the length of the hypotenuse. This sets you up with the relation
In 23, you're given a similar situation, except now you're looking for the angle (I'll call it
) in the triangle opposite the side denoting the height of the airplane. So this time,
Answer:
equation in terms of x is 18x - 12
x = 3
area = 104 sq. feet
you want only the ans right?
if you need explaination comment down.
GOOD LUCK FOR THE FUTURE! :)
To solve this, you distribute the -y to both terms, 2 and 4y.
It will look something like this: (2*-y)+(4y*-y)
When you simplify, look for any like terms that can be combined, and if none, then leave it as it is.
Your final answer will be: -2y-4y^2
