73.
a)
b)
Since we can't divide by zero, we need to find when:
But before, we can factor the numerator and the denominator:
Now, we can conclude that the vertical asymptotes are located at:
so, for x = -3:
For x = 4:
Rita and Tina each make $11 an hour working as cashiers at a supermarket. Last week, Rita worked r hours while Tina worked t hou
1 answer:
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Answer:
(a) As time increases, the amount of water in the pool increases.
11 gallons per minute
(b) 65 gallons
Step-by-step explanation:
From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.
We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.
The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).
Choose 2 ordered pairs from the table:
Input these into the slope formula:
Therefore, the rate at which the water in the pool is increasing is:
<u>11 gallons per minute</u>
To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:
When Ann had added no water, x = 0. Therefore,
So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.
Answer:
A. 10 + 2
Step-by-step explanation:
288 ÷ 24 is shown below. 240 ÷ 24 = 10 288 – 240 = 48 48 ÷ 24 = 2
After obtaining the quotient of 288 ÷ 24 = 10,
Multiplying the divisor 24 by 10 = 240 and subtracting 240 from 288 to obtain the remainder = 48, the divisor is again used in 48 and the quotient obtained is added to the intula quotient value of 10 ; (10 + 2) and the process repeated
