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3 years ago

Express 33 1/2% as fraction

1 answer:

8 0

First you have to multiply 2x33 which is 66 then you have to add 1 which is 67 so the answer would be 67/2 I don’t know about the percent sign though

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The measure of a square wall is 9 feet 7 inches on each side. Estimate the square feet a painter would have to cover to the near

Nookie1986 [14]

First, convert those inches to feet.
7in =ish 0.5833333
(you find this by dividing 7/12 on a calculator)
Now you just square 9.583333333
9.583333333^2
9.583333333 * 9.583333333
91.84027777ish
Rounded to the nearest foot, means the answer is 92ft.

5 0

3 years ago

Which equation represents the line that is perpendicular to y=1/5 and passes through (-4,-3)?

babymother [125]

Answer:

x=-4

Step-by-step explanation:

Just had it on a test and got it write

3 0

3 years ago

In a population of similar households, suppose the weekly supermarket expense for a typical household is normally distributed wi

Rina8888 [55]

Answer:

P(Y ≥ 15) = 0.763

Step-by-step explanation:

Given that:

Mean =135

standard deviation = 12

sample size n = 50

sample mean $\overline x$ = 140

Suppose X is the random variable that follows a normal distribution which represents the weekly supermarket expenses

Then,

$X \sim N ( \mu \sigma)$

The probability that X is greater than 140 is :

P(X>140) = 1 - P(X ≤ 140)

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{140-135}{12})$

$P(X>140) = 1 - P( \dfrac{X-\mu}{\sigma} \leq \dfrac{5}{12})$

$P(X>140) = 1 - P( Z\leq0.42)$

From z tables,

$P(X>140) = 1 - 0.6628$

$P(X>140) = 0.3372$

Similarly, let consider Y to be the variable that follows a binomial distribution of the no of household whose expense is greater than $140

Then;

$Y \sim Binomial (np)$

$Y \sim Binomial (50,0.3372)$

∴

P(Y ≥ 15) = 1- P(Y< 15)

P(Y ≥ 15) = 1 - ( P(Y=0) + P(Y=1) + P(Y=2) + ... + P(Y=14) )

$P(Y \geq 15) = 1 - \begin {pmatrix} ^{50}_0 \end {pmatrix} (0.3372)^0 (1-0,3372)^{50} + \begin {pmatrix} ^{50}_1 \end {pmatrix} (0.3372)^1 (1-0,3372)^{49} + \begin {pmatrix} ^{50}_2 \end {pmatrix} (0.3372)^2 (1-0,3372)^{48} +... + \begin {pmatrix} ^{50}_{50{ \end {pmatrix} (0.3372)^{50} (1-0,3372)^{0}$