Answer:Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Take half of the coefficient of x: It is 3, and half that is 3/2.
Then <span>x^2+3x=6 becomes:
</span><span> x^2+3x + (3/2)^2 =6 + (3/2)^2, and
(x+3/2)^2 = 6 + 9/4
You were not asked to solve the equation, but why not do it for the practice?
</span>Solve (x+3/2)^2 = 6 + 9/4 for x. There will be 2 values.
Answer:
1/8
Step-by-step explanation:
The slope equation for this problem is
y2-y1
--------
x2-x1
So the y2=4, y1=3, x2=8, and x1=0
4-3 =1
----- --
8-0 =8
Which is 1/8
Tbh idk I believe that the answer is 12
Answer:
Step-by-step explanation:
y = 3x+4 and y = x-2
3x+4 = x-2
2x+4 = -2
2x = -6
x = -3
y = -3 -2 = -5