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xz_007 [3.2K]
3 years ago
11

Josiah cell phone plan allows a number of minutes of air time for $20 a month each minute costs 0.02 $ how many minutes of air t

ime is he allowed?
Mathematics
1 answer:
Keith_Richards [23]3 years ago
3 0

Given parameters:

Cost of cell phone plan per minute  = 0.02$/min

Amount in a month  = $20

Unknown:

Number of minutes allowed per month?

Solution:

 The number of minutes = \frac{amount per month}{rate per call}

     Input the parameters and solve;

                                         = \frac{20}{0.02}

                                         = 1000min

The number of minutes allowed per month is 1000min

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The present age of the father is twice the age of his daughter. Ten years ago, the
Elenna [48]

Answer:

<h3>           The father is 40 and the daughter is 20.</h3>

Step-by-step explanation:

x           -  the present age of the daughter

2x         -  the present age of the fathter  

x - 10          -  the age of the daughter ten year ago

2x - 10        -  the age of the fathter ten year ago

Father is older than his dauther, so:

2x - 10 = (x - 10) + 20  

2x - 10 = x - 10 + 20  

2x - 10 = x + 10              {subtract x from both sides}

x - 10 = 10                      {add 10 to both sides}

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6 0
3 years ago
WILL GIVE BRAINLIEST
Papessa [141]
<span>the particle's initial position is at t=0, x = 0 - 0 + 4 = 4m

velocity is rate of change of displacement = dx/dt = d(t^3 - 9t^2 +4)/dt
= 3t^2 - 18t

acceleration is rate of change of velocity = d(3t^2 -18t)/dt
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</span><span>the particle is stationary when velocity = 0, so 3t^2 - 18t =0
</span>3t*(t - 6) = 0
t = 0 or t = 6s

acceleration = 6t - 18 = 0
t = 3s
at t = 3s, velocity = 3(3^2) -18*3 = -27m/s
displacement = 3^3 - 9*3^2 +4 = -50m


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