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3 years ago

8

Over which interval is the graph x^2+3x+8 increasing

1 answer:

vladimir1956 [14]3 years ago

7 0

F(x) = <span>x^2+3x+8

now, the pending of the tangent line is d/dx f(x)
f'(x) = 2x + 3
now, we need know when the pending is increasing.
so
</span>2x + 3> 0

solving
x>-3/2

The interval over which the function f(x)= x^2+3x+8 is <span>increasing is (-3/2,+</span>∞<span>)</span><span>
</span>

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3 years ago

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2 years ago

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see the attached figure

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3 years ago