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zubka84 [21]
3 years ago
6

Factor 2x2 - 10x + 8 completely.

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

c. 2(x-1)(x-4)

Step-by-step explanation:

c. 2(x-1)(x-4)

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What's 9-2x=35<br><br><br><br><br><br>please need help and explain it ​
Degger [83]

Answer:

x = -13

Step-by-step explanation:

9 - 2x = 35

<u>-9           -9 </u>

-2x = 26

divide by -2

x = -13

6 0
3 years ago
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He buys a jewel for $180, then sells it for $216. Find his percentage profit.
yan [13]

Answer:20%

Step-by-step explanation:216-180=36. 36/180=.20

6 0
2 years ago
HERE IS THE ONE WITH THE QUESTION LOL PLZ ANSWER
ZanzabumX [31]

Answer:  

The graph goes with the third chart  

Step-by-step explanation:

Y starts at 3 and then goes up to 4,5, and then 6 while x starts at 0 and goes up to 1,2, and 3

8 0
3 years ago
A line passes through the point (–6, –3) and has a slope of 2/3 . Which point is on the same line?
navik [9.2K]

Answer:

The point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

Step-by-step explanation:

We know that the slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

Given

  • The point (-6, -3)
  • The slope m = 2/3

Using the point-slope form

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

In our case:

  • m = 2/3
  • (x₁, y₁) = (-6, -3)

substituting the values m = 2/3 and the point (-6, -3)  in the point-slope form

y-y_1=m\left(x-x_1\right)

y-\left(-3\right)=\frac{2}{3}\left(x-\left(-6\right)\right)

y+3=\frac{2}{3}\left(x+6\right)

Subtract 3 from both sides

y+3-3=\frac{2}{3}\left(x+6\right)-3

y=\frac{2}{3}x+4-3

y=\frac{2}{3}x+1

comparing with the slope-intercept form y=mx+b

Here the slope = m = 2/3

Y-intercept b = 1

We know that the value of y-intercept can be determined by setting x = 0, and determining the corresponding value of y.

Given the line

y=\frac{2}{3}x+1

at x = 0, y = 1

Thus, the point (0, 1) represents the y-intercept.

Hence, the y-intercept (0, 1) is on the same line.

5 0
3 years ago
2x-y=5<br>2x-2y=4<br><img src="https://tex.z-dn.net/?f=2%20%5Ctimes%20%20-%20y%20%3D%205%20%5C%5C%202%20%5Ctimes%20%20-%202y%20%
d1i1m1o1n [39]
\left\{\begin{array}{ccc}2x-y=5\\2x-2y=4&|\cdot(-1)\end{array}\right\\\underline{-\left\{\begin{array}{ccc}2x-y=5\\-2x+2y=-4\end{array}\right}\ \ \ \ |add\ both\ sides\\.\ \ \ \ \ \ \ \ y=1\\\\substitute\ the\ value\ of\ y\ to\ first\ equation\\\\2x-1=5\ \ \ |+1\\2x=6\ \ \ |:2\\x=3\\\\\left\{\begin{array}{ccc}x=3\\y=1\end{array}\right
7 0
3 years ago
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