If mA=mB and mA + mC=D, then mB+mC=D, which property is shown?

Mathematics

2 answers:

otez555 [7]3 years ago

8 0

Answer:In our case, A is mB, B is mB .

Step-by-step explanation:

Andru [333]3 years ago

5 0

In the case : <span>If mA=mB and mA + mC=D, then mB+mC=D the </span>Transitive Property is shown.The transitive property states that if A=B and B=C, then A=C. In our case, A is mB, B is mB .

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romanna [79]

Since the tangent of B is 4/3, then:

$\begin{gathered} \frac{AC}{BA}=\frac{4}{3} \\ \Rightarrow AC=\frac{4}{3}BA \end{gathered}$

On the other hand, since ABC is a right triangle with hypotenuse BC, then:

$(BA)^2+(AC)^2=(BC)^2$

Substitute AC=3/4 BA and BC=15 to find BA:

$\begin{gathered} (BA)^2+(\frac{4}{3}BA)^2=15^2 \\ \Rightarrow BA^2+\frac{16}{9}BA^2=15^2 \\ \Rightarrow(1+\frac{16}{9})BA^2=15^2 \\ \Rightarrow\frac{25}{9}BA^2=15^2 \\ \Rightarrow BA^2=\frac{9}{25}\cdot15^2 \\ \Rightarrow BA=\sqrt[]{(\frac{9}{25}\cdot15^2)} \\ \Rightarrow BA=\frac{3}{5}\cdot15 \\ \Rightarrow BA=9 \end{gathered}$

Substitute BA=12 into the expression for AC to find its value: