Answer:
(A) ![A=\left[\begin{array}{ccc}10&20&40\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%2620%2640%5Cend%7Barray%7D%5Cright%5D)
(B) ![B=\left[\begin{array}{ccc}11&22&44\end{array}\right]](https://tex.z-dn.net/?f=B%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%2622%2644%5Cend%7Barray%7D%5Cright%5D)
(C) ![A+B=\left[\begin{array}{ccc}21&42&84\end{array}\right]](https://tex.z-dn.net/?f=A%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%2642%2684%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
The manager ordered 10 lb of tomatoes, 20 lb of zucchini, and 40 lb of onions from a local farmer one week.
(A)
Matrix <em>A</em> represents the amount of each item ordered. It is 1 × 3 matrix.
Then matrix <em>A</em> is:
(B)
Next week the manager increases the order of all the products by 10%.
Then the amount of new orders are:
Tomatoes ![=10\times [1+\frac{10}{100}]=10\times1.10=11](https://tex.z-dn.net/?f=%3D10%5Ctimes%20%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%3D10%5Ctimes1.10%3D11)
Zucchini ![=20\times [1+\frac{10}{100}]=20\times1.10=22](https://tex.z-dn.net/?f=%3D20%5Ctimes%20%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%3D20%5Ctimes1.10%3D22)
Onions ![=40\times [1+\frac{10}{100}]=40\times1.10=44](https://tex.z-dn.net/?f=%3D40%5Ctimes%20%5B1%2B%5Cfrac%7B10%7D%7B100%7D%5D%3D40%5Ctimes1.10%3D44)
Th matrix <em>B</em> represents the amount of each order for the next week. Then matrix <em>B</em> is:
(C)
Add the two matrix <em>A</em> and <em>B</em> as follows:
![A+B=\left[\begin{array}{ccc}10&20&40\end{array}\right]+\left[\begin{array}{ccc}11&22&44\end{array}\right]\\=\left[\begin{array}{ccc}(10+11)&(20+22)&(40+44)\end{array}\right]\\=\left[\begin{array}{ccc}21&42&84\end{array}\right]](https://tex.z-dn.net/?f=A%2BB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%2620%2640%5Cend%7Barray%7D%5Cright%5D%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D11%2622%2644%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%2810%2B11%29%26%2820%2B22%29%26%2840%2B44%29%5Cend%7Barray%7D%5Cright%5D%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%2642%2684%5Cend%7Barray%7D%5Cright%5D)
The entries of the matrix (<em>A</em> + <em>B</em>) represent the amount of tomatoes, zucchini and onions ordered for two weeks.
A)
First note that the plates can have between 4 and 6 symbols so we will need to find the number of plates with 4 symbols, 5 symbols and 6 symbols. We add these to get the total. In this part repetition of symbols is allowed. Since there are 26 + 10 =36 possible symbols we look at each position on the plate and think of how many choices there are. We multiply the number f choices using the counting principal since the choices are each independent -- one symbol does not affect another. There are 36 choices for the first symbol, 35 for the second and so on. The number of plates is:
4-symbols = (36)(36)(36)(36)=36^4
5 symbols = (36)^5
6 symbols = 36^6
So the total here is: 36^4+36^5+36^6
B) Here we do not repeat symbols so there are 36 choices for the first symbol but only 35 for the next and 34 for the one after and so on.
4-symbols = (36)(35)(34)(33)
5 symbols = (36)(35)(34)(33)(32)
6 symbols = (36)(35)(34)(33)(32)(31)
So the total here is: (36)(35)(34)(33)+(36)(35)(34)(33)(32)+(36)(35)(34)(33)(32)(31)
c)
In order for there to be a repeated symbol we have 36 choices for the first symbol, 36 for the next and so on. However, for the last symbol we have to pick from one of the ones already selected so there are 3, 4 or 5 choices respectively.
4-symbols = (36)(36)(36)(3)
5 symbols = (36)(36)(36)(36)(4)
6 symbols = (36)(36)(36)(36)(36)(5)
So the total here is: (36^3)(3)+(36^4)(4)+(36^5)(5)
D)
The probability is given by (the number of plates with at least one repeated symbol)/(the total number of plates if repetitions are allowed) = (the answer to c) / (the answer to a)
Answer:
its D
Step-by-step explanation:
(fg)(x) = [f(x)][g(x)]
(fg)(x) = (4x - 5)(3) = 12x - 15
5B + B = 20
6B = 20
B = 20 / 6
= 10/ 3 hrs
A = 5 ( 10/3 + 2)
= 5 (16/3)
= 80 / 3 hrs
Brian traveled 10/3 hours and Annie traveled 80/3 hours.
