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3 years ago

HELP!!! WILL MARK BRAINLIEST!!!

Mathematics

1 answer:

Fofino [41]3 years ago

5 0

Answer:

the answer is function 1 has the larger max. at (4,1)

Step-by-step explanation:

draw function 2 : the vertex is (1,-2)

the vertex of function 1 is (4,1)

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Find the mean median mode and range for the following data 77 60 59 70 89 95

Advocard [28]

Answer:

Mean = 75

Median = 73.5

Mode = 95

Range = 36

Step-by-step explanation:

Given:

77,60,59,70,89,95

Sort:

59,60,70,77,89,95

To find:

Mean
Median
Mode
Range

Mean:

$\displaystyle \large{\dfrac{1}{n}\sum_{i =1}^n x_i = \dfrac{x_1+x_2+x_3+...+x_n}{n}}$

Sum of all data divides by amount.

$\displaystyle \large{\dfrac{59+60+70+77+89+95}{6}=\dfrac{450}{6}}\\\\\displaystyle \large{\therefore mean=75}$

Therefore, mean = 75

Median:

If it’s exact middle then that’s the median. However, if two data or values happen to be in middle:

$\displaystyle \large{\dfrac{x_1+x_2}{2}}$

From 59,60,70,77,89,95, since 70 and 77 are in middle:

$\displaystyle \large{\dfrac{70+77}{2} = \dfrac{147}{2}}\\\displaystyle \large{\therefore median = 73.5}$

Therefore, median = 73.5

Mode:

The highest value or/and the highest amount of data. Mode can have more than one.

From sorted data, there are no repetitive data nor same data. Consider the highest value:

Therefore, mode = 95

Range:

$\displaystyle \large{x_{max}-x_{min}}$ or highest value - lowest value

Thus:

$\displaystyle \large{95-59 = 36}$

Therefore, range = 36

7 0

2 years ago

Given: F(x) = 2x + 3, find F(X+h)-f(x) and simplify. 01 02 (2h+6)/h

antiseptic1488 [7]

F(x+h) = 2(x+h) +3= 2x + 2h +3
f(x) = 2x + 5

f(x+h) - f(x) = 2x + 2h + 3- 2x - 3= 2h

[f(x+h) - f(x)]/h = 2h/h = 2

6 0

3 years ago

HELP!!! 30 POINTS!!

FromTheMoon [43]

Answer:

1. A.) 300 cm

2. D.) 1700 in

3. A.) 12 cm

4. B.) 421 FT

Step-by-step explanation:

4 0

3 years ago

CDEF is a kite and FCE = 34 . Find m1.

klio [65]

<FCE = 34

<1 = <FCE = 34

34Therefore angle 1=44

4 0

3 years ago

A club consisting of 6 juniors and 8 seniors is to be formed from a group of 13 juniors and 16 seniors. How many different clubs

Vilka [71]

Answer: 22,084,920 different clubs

Step-by-step explanation:

The club must have 6 juniors and 8 seniors

We have a total of 13 juniors and 16 seniors.

Now, we know that the possible combinations of N objects into a group of K is equal to:

$C = \frac{N!}{(N-K)!*K!}$

For the juniors we have N = 13 and K = 6

$Cj = \frac{13!}{7!*6!} = \frac{13*12*11*10*9*8}{6*5*4*3*2*1} = 1716$

For the seniors we have N = 16 and K = 8

$Cs = \frac{16!}{8!8!} = \frac{16*15*14*13*12*11*10*9}{8*7*6*5*4*3*2*1} = 12870$

Now, as the group consist on both combinations togheter, the number of different clubs that can be formed are:

C = Cj*Cs = 1,716*12,870 = 22,084,920

5 0

3 years ago