Answer:
x = 12
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The square of the tangent is equal to the product of the external part and the entire secant, that is
x² = 6(6 + 18) = 6 × 24 = 144 ( take the square root of both sides )
x = 
= 12
Answer: x ≥ 6
<u>Step-by-step explanation:</u>
12 less <u>than</u> 5 times a number ≥ 6 more <u>than</u> twice the number
5x - 12 ≥ 2x + 6
Note: the word "than" switches the order of the terms.
5x - 12 ≥ 2x + 6
<u>-2x +12</u> <u>-2x +12 </u>
3x ≥ 18
<u>÷3 </u> <u> ÷3 </u>
x ≥ 6
Graph: 6 -----------→ the dot is closed (filled in) since it is "equal to"
Answer:
Step-by-step explanation:
1/5* 1/4 * 1/3
I think it is the second one
one fifth
one fourth
one third
The solutions are where these two functions intersect, that is, at x = -4 and x = -6. The answer is C.
the domain of f(x)=9-x^2 is (-∞,∞), {x|x ∈r}
