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ladessa [460]
3 years ago
11

The function f(x)=(x-1)^2+5 is not one-to-one

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0

Answer:

True

Step-by-step explanation:

If x = 2 Than (x-1)^2 = 1

If x= 0 than (x-1)^2 = 1

For a one to one function this cannot happen as there x determines f(x) but also f(x) determines x.

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40 tens.how many hundreds
Sladkaya [172]
400. Just add a zero when you're dealing with tens
7 0
3 years ago
What is the equation of the line that passes through the points (3,-2) and (6,3)?
cupoosta [38]

Answer: m=5/3

Step-by-step explanation:

i think its right

4 0
3 years ago
What is the mean of these groups of numbers? 1,1,5,3,6,6
igor_vitrenko [27]
Mean
add up numbers and divide by how many there are
(1+1+5+3+6+6)/7=3 and 2/3
8 0
3 years ago
Read 2 more answers
Please help me I need help please​
MakcuM [25]

Answer:

p = 4

Step-by-step explanation:

Given equation:

x^2+(p-3)y^2-4x+6y-16=0

<u>Standard equation of a circle:</u>

(x-a)^2+(y-b)^2=r^2

(where (a,b) is the centre of the circle, and r is the radius)

If you expand this equation, you will see that the coefficient of y^2 is always one.

Therefore, p-3=1

\implies p=1+3=4

<u>Additional information</u>

To rewrite the given equation in the standard form:

\implies x^2+y^2-4x+6y-16=0

\implies x^2-4x+y^2+6y=16

\implies (x-2)^2-4+(y+3)^2-9=16

\implies (x-2)^2+(y+3)^2=16+4+9

\implies (x-2)^2+(y+3)^2=29

So this is a circle with centre (2, -3) and radius √29

3 0
2 years ago
Which expression can be substituted for y in the top equation of the
maria [59]

Answer:

Y=7+3x, x=-3, y=-2

Step-by-step explanation:

3x-5y=1. Equation 1

3x-y=-7. Equation 2

-y=-7-3x isolate for y in equation 2

y=7+3x multiplied by -1 to get positive y

3x-5(7+3x)=1 substitute y value of equation 2 (7+3x) into equation 1

3x-35-15x=1

-12x=36

x=-3

solve for y.

3x-5y=1

3(-3)-5y=1

-9-5y=1

-5y=10

y=-2

6 0
3 years ago
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