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trasher [3.6K]
3 years ago
5

Which expressions are equivalent to the one below? Check all that apply.log 2 - log 6

Mathematics
2 answers:
Marina CMI [18]3 years ago
7 0

Answer:

Given the expression: log 2 -log 6

Use the logarithmic rule :

\log(\frac{m}{n}) = \log m - \log n

\log x^n = n\log x

Use the above rule to solve the expression:

\log 2 -\log 6 = \log \frac{2}{6} = \log \frac{1}{3}   [∴\log(\frac{m}{n}) = \log m - \log n ]

or

\log 2 -\log 6 =\log 2+ \log 6^{-1} = \log 2 + \log \frac{1}{6}     [∴\log x^n = n\log x ]

or

value of : log 2 -log 6 = 0.30102999566 - 0.77815125038 = -0.47712125472



AVprozaik [17]3 years ago
3 0
There are no correct expressions listed.

Log(2) - log(6) is equivalent to

log(1/3)
or
-log(3)
or
-0.47712...
or
any one of a bunch of others.
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