Let d represent the distance of the destination from the starting point.
After 45 min, Henry has already driven d-68 miles. After 71 min., he has already driven d-51.5 miles.
So we have 2 points on a straight line:
(45,d-68) and (71,d-51.5). Let's find the slope of the line thru these 2 points:
d-51.5 - (d-68) 16.5 miles
slope of line = m = ----------------------- = ------------------
71 - 45 26 min
Thus, the slope, m, is m = 0.635 miles/min
The distance to his destination would be d - (0.635 miles/min)(79 min), or
d - 50.135 miles. We don't know how far his destination is from his starting point, so represent that by "d."
After 45 minutes: Henry has d - 68 miles to go;
After 71 minutes, he has d - 51.5 miles to go; and
After 79 minutes, he has d - x miles to go. We need to find x.
Actually, much of this is unnecessary. Assuming that Henry's speed is 0.635 miles/ min, and knowing that there are 8 minutes between 71 and 79 minutes, we can figure that the distance traveled during those 8 minutes is
(0.635 miles/min)(8 min) = 5.08 miles. Subtracting thix from 51.5 miles, we conclude that after 79 minutes, Henry has (51.5-5.08), or 46.42, miles left before he reaches his destination.
Answer:
Equation of a line is y = mx + c
Where m is the slope
c is the y intercept
Equation of the line using point
( 1 , - 4) and slope 5/2 is
Hope this helps you
-3/2
slope = rise/run
We can use the two points to calculate rise (y value change) and run (x value change)
slope = (-6)/4 = -3/2
Answer:
11.7 units
Step-by-step explanation:
sq root(2--4)^2+(-7-3)^2
sq root(6)^2 + (-10)^2
sq root (36)+(100)
sq root 136
equals 11.66 which rounds up to 11.7
