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Nady [450]
4 years ago
9

By what factor would you need to multiply the first and second equations to eliminate x? By what factor would you need to multip

ly the second and third equations to eliminate x?
Mathematics
1 answer:
gavmur [86]4 years ago
4 0
Equation 1 : x + y + z = 3.25
equation 2 : 12x + 2y + z = 9.50
equation 3 : 2x + 4y + 5z = ??

u would multiply equation 1 by -12.....take that result and add it to equation 2....this eliminates x.

u would multiply equation 3 by -6...take that result and add it to equation 2....this eliminates x


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coldgirl [10]

Answer:

Natural numbers,integers, rational numbers, irrational numbers.

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3 years ago
Factor Completely: 100x2 - 1
fredd [130]

Answer:

d

Step-by-step explanation:

100x² - 1 ← is a difference of squares and factors in general as

a² - b² = (a - b)(a + b), thus

100x² - 1

= (10x)² - 1²

= (10x - 1)(10x + 1) → d

3 0
3 years ago
What is an equation of the line passing between(4, -6) and (12, -8)?*
I am Lyosha [343]

Answer:

y= -1/4x - 5

Step-by-step explanation:

first you need to find the slope.

to do this you can use the equation: change in y/change in x which is also y2 - y1/x2-x1

-8 - (-6)/12-4

-2/8

-1/4 = slope

since the line's equation is y = mx + b, we still need to find the y-intercept. we can do this by just plugging in one of the points

-6 = -1/4(4) + b

-6 = -1 + b

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so the final equation is y= -1/4x - 5

4 0
3 years ago
Select the two values of x that are roots of this equation 3x^2 + 1 =5x
Zina [86]

Answer:

x = 1.434 and x=0.232

Step-by-step explanation:

To find the root of the equation stated above we need to:

(1) Write the polynomial equation with zero on the right hand side:

3x^{2} + 1 = 5x ⇒ 3x^{2} -5x + 1 = 0

(2) Divide the whole equation by 3

3x^{2} -5x + 1 = 0 ⇒ x^{2} -\frac{5}{3}x + \frac{1}{3}= 0

(3) Use the quadratic formula to solve the quadratic equation:

The quadratic formula states that the two solutions for a quadratic equation is given by:

\frac{-b±\sqrt{b^{2} - 4ac}}{2a} (1)

In this case, a = 1, b = -\frac{5}{3}, c= \frac{1}{3}

Substituiting a, b and c in equation (1) We get:

\frac{-\frac{5}{3}±\sqrt{(-\frac{5}{3})^{2} - 4(1)(\frac{1}{3})}}{2(1)} (1)

The two solutions are:

x = 1.434 and x=0.232

8 0
3 years ago
A number n is negative
Alborosie

Answer:

-n

Step-by-step explanation:

4 0
3 years ago
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